Convert variable-width text file numbers to UINT8 table?

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Bjoern
Bjoern 2014-6-27
回答： C.J. Harris 2014-6-27
Hi :)
I have a file holding UINT8 integers:
  • Each line contains 1 to 8 integers
  • Each line is of width = 3 + (N-1)*4; where N is number of integers
  • Each value reserves exactly 3 characters (with leading space)
  • Each value is space-separated
  • Each line is '' terminated
Below is an example format:
//File begins
130 216 165 154 233 210 209 129
63 17 228
2 27 13 94 6 29 0 0
7 114 2 0 61 100 71
81 3 2 15 15 8 13 7
//File ends
I need to read out this data to a UINT8 table per below but cannot figure out a good way. I'd like to use a similar approach to this other solution where loops are avoided for good performance:
Goal = uint8([130 216 165 154 233 210 209 129 ; ...
63 17 228 0 0 0 0 0 ; ...
2 27 13 94 6 29 0 0 ; ...
7 114 2 0 61 100 71 0 ; ...
81 3 2 15 15 8 13 7 ]);

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回答（1 个）

C.J. Harris
C.J. Harris 2014-6-27
It's not very elegant, and it's not very efficient - so enjoy:
nRaw = {'130 216 165 154 233 210 209 129'
' 63 17 228'
' 2 27 13 94 6 29 0 0'
' 7 114 2 0 61 100 71'
' 81 3 2 15 15 8 13 7'};
Goal = zeros(size(nRaw,1),8,'uint8');
for nRow = 1:size(nRaw)
Goal(nRow,:) = str2num(['uint8([',[nRaw{nRow}, char(repmat([32 32 32 48], ...
1, floor((31-length(nRaw{nRow}))/4)))],'])']);
end

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