After executing the code you will get one figure from that figure i want to find the nearer point of the '*'. Around that '*' point there are so many point's are there so i want to find that node (in figure nearer node is denoted as 'o')
how to get nearer point of cluster head in this code
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close all;
clear all;
%Field Dimensions - x and y maximum (in meters)
xm=100;
ym=100;
sink.x=0.5*xm;
sink.y=0.5*ym;
n=100;
p=0.1;
Eo=0.1;
ETX=50*0.000000001;
ERX=50*0.000000001;
Efs=10*0.000000000001;
Emp=0.0013*0.000000000001;
EDA=5*0.000000001;
m=0.1;
x=0.2;
a=1;
b=0.5;
rmax=5;
Ave_CH=0;
sum=0;
count_ch=0;
Throughput=0;
Packet=40;
do=sqrt(Efs/Emp);
figure(1);
for i=1:1:n
S(i).xd=rand(1,1)*xm;
XR(i)=S(i).xd
S(i).yd=rand(1,1)*ym;
YR(i)=S(i).yd
S(i).G=0;
S(i).E=0;
S(i).type='N'
keep(i)=i;
temp_rnd0=i;
if (temp_rnd0>=(x+m)*n+1)
S(i).E=Eo;
S(i).ENERGY=0;
plot(S(i).xd,S(i).yd,'o');
hold on;
end
end
S(n+1).xd=sink.x;
S(n+1).yd=sink.y;
figure(1);
countCHs=0;
rcountCHs=0;
cluster=1;
countCHs;
rcountCHs=rcountCHs+countCHs;
flag_first_dead=0;
flag_first_Hdead=0;
flag_last_dead=0;
c=1;
for r=0:1:rmax
for i=1:1:n
if(S(i).E>0)
holder(i)=S(i).E;
id(i)=keep(i);
node= struct('energy', holder, 'id',id);
[energy,index] = sort([node.energy],'descend');
end
end
total=0;
for k=1:length(node.energy)
energy_level=sort(node.energy, 'descend');
total=total + node.energy(k);
end
average=total/length(node.energy);
TEnergy(r+1)=total;
AveEnergy(r+1)=average;
r
%Election Probability for Normal Nodes
pnrm=( p/ (1+a*m+b*x) );
if(mod(r, round(1/pnrm) )==0)
for i=1:1:n
S(i).G=0;
S(i).cl=0;
end
end
end
Hdead=0;
dead=0;
packets_TO_BS=0;
packets_TO_CH=0;
PACKETS_TO_CH(r+1)=0;
PACKETS_TO_BS(r+1)=0;
figure(1);
for i=1:1:n
if (S(i).E<=(Eo/2)) && (S(i).E>0)
plot(S(i).xd,S(i).yd,'yellow .');
Hdead=Hdead+1;
if(S(i).ENERGY==1)
Hdead_a=Hdead_a+1;
end
hold on;
end
if (S(i).E<=Eo)||(S(i).E>Eo)
if(S(i).ENERGY==0)
RnEnergy(r+1)=S(i).E;
end
end
if (S(i).E<=0)
plot(S(i).xd,S(i).yd,'red .');
dead=dead+1;
if(S(i).ENERGY==1)
dead_a=dead_a+1;
end
hold on;
end
if S(i).E>0
S(i).type='N'
if (S(i).ENERGY==0)
plot(S(i).xd,S(i).yd,'o');
end
hold on;
end
end
plot(S(n+1).xd,S(n+1).yd,'x');
HSTATISTICS(r+1).DEAD=Hdead;
HDEAD(r+1)=Hdead;
if (Hdead==1)
if(flag_first_Hdead==0)
first_Hdead=r;
flag_first_Hdead=1;
end
end
STATISTICS(r+1).DEAD=dead;
DEAD(r+1)=dead;
if (dead==1)
if(flag_first_dead==0)
first_dead=r;
flag_first_dead=1;
end
end
alive=0;
for i=1:1:n
if (S(i).E>0)
alive=alive+1;
if(S(i).ENERGY==1)
alive_a=alive_a+1;
end
hold on;
end
if (S(i).E>0)
nodes_status=1;
end
if (S(i).E<0)
nodes_status=0;
end
ASTATISTICS(r+1).Live=alive;
Live(r+1)=alive;
end
countCHs=0;
cluster=1;
for i=1:1:n
if(S(i).E>0)
temp_rand=rand;
if ( (S(i).G)<=0)
if( ( S(i).ENERGY==0 && ( temp_rand <= ( pnrm / ( 1 - pnrm * mod(r,round(1/pnrm)) )) ) ) )
countCHs=countCHs+1;
packets_TO_BS=packets_TO_BS+1;
PACKETS_TO_BS(r+1)=packets_TO_BS;
S(i).type='C'
S(i).G=100;
C(cluster).xd=S(i).xd
C(cluster).yd=S(i).yd
plot(S(i).xd,S(i).yd,'red+');
distance=sqrt( (S(i).xd-(S(n+1).xd) )^2 + (S(i).yd-(S(n+1).yd) )^2 );
C(cluster).distance=distance
C(cluster).id=i
X(cluster)=S(i).xd
Y(cluster)=S(i).yd
cluster=cluster+1;
distance;
if (distance>do)
S(i).E=S(i).E-((ETX+EDA)*(Packet)+Emp*Packet*( distance*distance*distance*distance ));
Energy_CH_N=(ETX+EDA)*(Packet) + Emp*Packet*( distance*distance*distance*distance );
end
if (distance<=do)
S(i).E=S(i).E- ( (ETX+EDA)*(Packet) + Efs*Packet*( distance * distance ));
Energy_CH_N=(ETX+EDA)*(Packet) + Emp*Packet*( distance*distance);
end
end
end
end
end
warning('OFF');
[vx,vy]=voronoi(X,Y);
voronoi(X,Y);
axis([0 xm 0 ym]);
回答(1 个)
Image Analyst
2014-7-16
Won't the Pythagorean theorem work for you? Say you have all the coordinates in x and y and some particular point you're interested in in (xp,yp). Calculate all the distances
distances = sqrt((x-xp).^2 + (y-yp).^2);
Then find the min
[minDistance, indexOfMin] = min(distances);
Make sure your xp,yp is not in the x and y or else the min will be zero and you don't want that case.
4 个评论
Image Analyst
2014-7-20
I see blue circles with blue crosses, I see red spots, I see blue hollow circles, and I see a blue x, plus of course a ton of uncommented code that probably no one is going to dive into unless comments are added. And I still don't know what context you're using "nearer" in. Again, nearer than what to what? For example, I am nearer to the door than you, meaning that the door is closer to me than it is to you. Nearer is relative - you have 3 things, a "destination/target/goal" and two other "things", one of which is nearer to the destination than the other. What are your 3 things? Are you sure you don't mean "nearest" rather than "nearer"???
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