If-then with a range

son
2014 7 28
1 个回答
回答已采纳
更新时间：2014 7 28
6 次查看（30 天）

0 个投票

Hi everyone, please help,
M is from 1 to 10 ( 1,2,3....,10)
if M is odd then N = M + 1 else N = M + 2
I created this file but the answer is wrong
close all
clear all
M=1:1:10;
if (mod(M,2)==1)
N=M+1;
else
N=M+2;
end
Matlab give N = 3 4 5 6 7 8 9 10 11 12
but it should be
N = 2 4 4 6 6 8 8 10 10 12

请先登录，再回答此问题。

 采纳的回答

Ben11
Ben11 2014-7-28
编辑：Ben11 2014-7-28

0 个投票

You're almost there!
clear
clc
M = 1:10;
N = zeros(1,length(M));
for k = 1:length(M)
if mod(M(k),2) == 1
N(k) = M(k)+1;
else
N(k) = M(k)+2;
end
end
N
N =
2 4 4 6 6 8 8 10 10 12

6 个评论
显示 4更早的评论 隐藏 4更早的评论

son
son 2014-7-28
the answer should be N = 2 4 4 6 6 8 8 10 10 12
Ben11
Ben11 2014-7-28
编辑：Ben11 2014-7-28
oups brain freeze sorry I edited my answer. I changed mod(M,2) == 0 to mod(M(k),2) == 1.
son
son 2014-7-28
it is perfect. many thanks to you.
Ben11
Ben11 2014-7-28
great you're very welcome!
son
son 2014-7-28
编辑：son 2014-7-28
one more question how to calculate the sum of all the N.
Ben11
Ben11 2014-7-28
sum(N) should do it

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Get Started with MATLAB 的更多信息

标签

尚未输入任何标签。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by