Matlab FOR Loop help!

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Dylan Flores 2014-7-29

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编辑： Ben11 2014-7-30

_ I'm trying to get this function to work. But i keep getting an error. I am trying to determine the amount in the savings account for next 18 years, which is represented by x(k) in an array. Problem is that only the first value for the first month shows up in the array._ * _ * _

clc,clear
% Variable declaration
% x will be used to store the value of the new balance
% a will be used to store the value of the old balance
% i will be used to store the value of the interest rate
% c will be used to store the value of the user's contribution
% Variable initialization
a = input('Enter a value for the initial balance: ');
i = input('Enter a value for the interest rate: ');
c = input('Enter a value that you will contribute: ');
% Calculation
month = 1:12:216;
x=zeros(length(month));
for k=1:length(month);
  x(k) = a + i(k) + c
end

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Sara 2014-7-29

在 MATLAB Online 中打开

Old balance is x(k-1) not a and I think interest means x(k-1)*i. The loop becomes:

x(1) = a;
for k = 2:numel(month)
  x(k) = x(k-1)+ x(k-1)*i + c; %or x(k-1)*(i+1) + c;
end

If the interest is %, divide i by 100.

Dylan Flores 2014-7-29

Thanks! It works a lot better now!

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回答（1 个）

Ben11 2014-7-29

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编辑：Ben11 2014-7-30

在 MATLAB Online 中打开

Maybe try this:

month = 1:12:216;
x=zeros(1,length(month)); % otherwise you have a 18*18 array
x(1) = a;
for k=2:length(month);
x(k) = x(k-1) + (i/100)*x(k-1) + c; % add the amount present during the previous month. Oh and I divided your interest rate by 100.
end