How to average first two dimension of 3D array/matrix?

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UTKARSH VERMA
UTKARSH VERMA 2021-9-1
评论： UTKARSH VERMA 2021-9-1
Hi all,
I am calculating the average of first two dimension of a 3D matrix but it is showing following error:
Error using sum
Dimension argument must be a positive integer scalar within indexing range.
Error in mean (line 116)
y = sum(x, dim, flag) ./ size(x,dim);
Also, I have used a simplest example given in topic 'Mean of Array Page' in https://in.mathworks.com/help/matlab/ref/mean.html but I am getting same error.
I am using MATLAB 2018a
Please help!
Thanks in advance
  2 个评论
UTKARSH VERMA
UTKARSH VERMA 2021-9-1
I have used a simplest example given in topic 'Mean of Array Page' in https://in.mathworks.com/help/matlab/ref/mean.html and I got an error:-
""Error using sum
Dimension argument must be a positive integer scalar within indexing range.
Error in mean (line 116)
y = sum(x, dim, flag) ./ size(x,dim);""
I guess my Matlab version is older (i.e. 2018a)

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采纳的回答

Chunru
Chunru 2021-9-1
编辑：Chunru 2021-9-1
Ran in:
a = randi(3, 3, 4, 2)
a =
a(:,:,1) = 3 3 1 3 3 1 2 3 3 1 3 1 a(:,:,2) = 3 1 1 2 1 1 2 2 1 3 1 1
c = mean(reshape(a, [], size(a,3)))
c = 1×2
2.2500 1.5833

更多回答（2 个）

Wan Ji
Wan Ji 2021-9-1
编辑：Wan Ji 2021-9-1
Just use mean function to average first two dimension of 3D matrix
a = rand(2,3,4); % I just use rand function so the result is randomly displayed
b = mean(a,1:2) % 1:2 means the first two dimension
The result is
b = mean(a,1:2)
b(:,:,1) =
0.5258
b(:,:,2) =
0.2759
b(:,:,3) =
0.6214
b(:,:,4) =
0.4449
If you want to get array of b
Then
b = squeeze(b) % or b = b(:);
So
b =
0.5258
0.2759
0.6214
0.4449
  1 个评论
UTKARSH VERMA
UTKARSH VERMA 2021-9-1
Thank you for replying.
I guess my Matlab version is older (i.e. 2018a) due to which I am not able to get my result and it's showing same problem.

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Steven Lord
Steven Lord 2021-9-1
The ability to specify a vector of dimensions over which to sum an array was introduced in release R2018b as stated in the Release Notes.

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