Interpolate/Resample to a specific decimal point

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a j
a j 2021-9-21
评论： a j 2021-9-21
I've got a cell array with different values in each array, sampled at different points. These points are random. I'm currently trying to figure out a way to resample+interpolate them in such a way that I can average over each cell row in the cell array. for example,
x{2}=[1 3 4 7 6 3 6]
should become
x{2}=[1 2 3 4 5 6 7 6 5 4 3 4 5 6]
I've looked into functions like interp1 and resample, but these assume that you have a vector of points you want to get or the target number of samples. I know neither. The ideal function would be something that takes in the intial vector(x{2}) and the desired sampling interval (1). How can I go about solving this problem?
  2 个评论
Matt J
Matt J 2021-9-21
编辑：Matt J 2021-9-21
Suppose your sampling interval was 1, but your initial vector was
x=[1 3.17 4 7.8 6 3 6]
What result would you expect?
Or, what if your input vector was still
x=[1 3 4 7 6 3 6]
but your sampling interval was 1.6? What result would you expect then?
a j
a j 2021-9-21
I should've added this in the post, but my data will always have the same number of digits after the decimal point. For the first one, I would have 2 digits after the decimal point, so my sampling interval would be .01, and I'd have a vector that would be [1 1.01 1.02 .... 3.17 3.18....].

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采纳的回答

Stephen23
Stephen23 2021-9-21
Ran in:
Assuming no adjacent duplicate values:
S = 1;
V = [1,3,4,7,6,3,6];
X = cumsum([1,abs(diff(V))]);
Z = interp1(X,V,1:S:X(end))
Z = 1×14
1 2 3 4 5 6 7 6 5 4 3 4 5 6

更多回答（1 个）

Mathieu NOE
Mathieu NOE 2021-9-21
hello
try this :
x=[1 3 4 7 6 3 6];
out = my_resample(x)
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
function out = my_resample(x)
out = [];
for ci = 2:length(x)
delta = sign(x(ci) - x(ci-1));
tmp = x(ci-1):delta:x(ci);
out = [out tmp(1:end-1)];
end
out = [out x(end)]; % include last value
end
it gives :
out = 1 2 3 4 5 6 7 6 5 4 3 4 5 6

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