Intersection of two lines

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Gaetano Pavone
Gaetano Pavone 2021-9-21
编辑： Matt J 2021-9-21
Hi, I have four coplanar points P1, P2, P3 and P4 in 3d. I would like to calculate the intersection point among the line passing through P1 and P2 and that passing through P3 and P4.
Moreover I would like to evaluate the angle between the vector connecting such intersection and the origin with z-axis and then plot the vector.

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Matt J
Matt J 2021-9-21
编辑：Matt J 2021-9-21
You need a least squares solution, since lines in 3D do not generally intersect. Assuming your point data are in column-vector form, this is,
c=[P2-P1,P3-P4]\(P3-P1);
P_intersection=P1+c(1)*(P2-P1)
angle=acos(P_intersection(3)/norm(P_intersection))
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Gaetano Pavone
Gaetano Pavone 2021-9-21
For
P1=[735;234;1397];
P2=[234;735;1397];
P3=[-265;234;1397];
P4=[234;-265;1397];
c=[P2-P1,P3-P4]\[-P1,P3];
P_intersection=P1+c(1)*(P2-P1);
angle=acos(P_intersection(3)/norm(P_intersection));
it doesn't give me the correct answer.
P_intersection should be [234;234;1397].
Matt J
Matt J 2021-9-21
编辑：Matt J 2021-9-21
Ran in:
You seem to have had P2 and P3 interchanged.
P1=[735;234;1397];
P3=[234;735;1397];
P2=[-265;234;1397];
P4=[234;-265;1397];
c=[P2-P1,P3-P4]\(P3-P1); %edited
P_intersection=P1+c(1)*(P2-P1)
P_intersection = 3×1
234 234 1397

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