Is there a way to capture the last 50 values without using 50 delay blocks?

1 次查看(过去 30 天)
I want to compare the last 50 values and only allow new values if the last 50 were equal. Currently I'm doing that with 5 values by using delay blocks:
Is there a way to achieve this without delay bocks? I don't think it's good practice to use 50 delay blocks ...

回答(1 个)

black_cat
black_cat 2021-9-22
Solved it by using a low-pass filter. :)

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