How I can plot time on x axis with a interval of 2hrs from 0 to 24hrs

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Vikash Raj 2021-9-30

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评论： Vikash Raj 2021-10-4

Hi.

I have a 10600 timestamp data in the form of 2015 - 01 -19T12:55:18Z which I need to plot aginst vertical total electron content. How can I remove T and Z and howI can plot time on x axis with a interval of 2hrs from 0 to 24hrs against vertical total electron content. Im very new to matlab software and Im doing a masters program to do my data analysis. Any help and suggestion will be highly appriciated.

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Walter Roberson 2021-9-30

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在 MATLAB Online 中打开

TS = {'2015 - 01 -19T12:55:18Z', '2015 - 01 -19T23:17:29Z', }

TS = 1×2 cell array

{'2015 - 01 -19T12:55:18Z'} {'2015 - 01 -19T23:17:29Z'}

t = datetime(TS, 'inputformat', "yyyy - MM -dd'T'HH:mm:ss'Z'", 'TimeZone', 'GMT')

t = 1×2 datetime array

19-Jan-2015 12:55:18 19-Jan-2015 23:17:29

plot(t, [1 2])

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Walter Roberson 2021-9-30

在 MATLAB Online 中打开

t = datetime('now') + sort(minutes(randi([0 24*60], 1, 30)))

t = 1×30 datetime array

30-Sep-2021 21:49:07 30-Sep-2021 22:15:07 30-Sep-2021 22:38:07 30-Sep-2021 23:02:07 30-Sep-2021 23:09:07 01-Oct-2021 00:45:07 01-Oct-2021 01:18:07 01-Oct-2021 02:52:07 01-Oct-2021 04:23:07 01-Oct-2021 05:35:07 01-Oct-2021 06:04:07 01-Oct-2021 06:30:07 01-Oct-2021 08:25:07 01-Oct-2021 08:34:07 01-Oct-2021 08:49:07 01-Oct-2021 09:28:07 01-Oct-2021 10:17:07 01-Oct-2021 10:42:07 01-Oct-2021 11:31:07 01-Oct-2021 11:44:07 01-Oct-2021 12:03:07 01-Oct-2021 14:27:07 01-Oct-2021 14:52:07 01-Oct-2021 15:42:07 01-Oct-2021 16:37:07 01-Oct-2021 17:48:07 01-Oct-2021 18:57:07 01-Oct-2021 19:48:07 01-Oct-2021 20:32:07 01-Oct-2021 21:12:07

y = rand(size(t))

y = 1×30

0.5071 0.2970 0.6975 0.0170 0.4546 0.5702 0.4778 0.8475 0.2032 0.9529 0.2908 0.2385 0.7161 0.6557 0.0726 0.3264 0.2269 0.2628 0.1820 0.3982 0.3167 0.2207 0.9381 0.6914 0.6869 0.5304 0.3496 0.8455 0.5153 0.9506

plot(datenum(t), y)

datetick('x', 'HH')

Is it possible that what you tried was more like

x = 0:2:24

x = 1×13

0 2 4 6 8 10 12 14 16 18 20 22 24

y = rand(size(x))

y = 1×13

0.9212 0.8744 0.2187 0.7557 0.2641 0.1259 0.0031 0.0706 0.5817 0.2496 0.2765 0.0463 0.8021

plot(x, y)

datetick('x', 'HH')

If so then the mistake would be that date numbers for datetick purposes are in days, so 0:2:24 would be 0, 2, 4, 6, ... 24 days, midnight each time

Walter Roberson 2021-10-1

Monthly... so each plot should have between 28*12 = 296 and 31*12 = 334 hour ticks ? So barely possible to make out at anything less than 1500 pixels wide ?

Vikash Raj 2021-10-4