How to Convert vector elements to zero for certain N length when its values gets negative?

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Sagar Dhage
Sagar Dhage 2014-8-6
评论： Sagar Dhage 2014-8-7
I have a column vector F= (0; 0; 0; 0; 5; 7; 12; 11; 23; 32; 22; 10; 8; -6 0; -8; 1; 4; 8; -5; 0; 0; 0; 6; 8; 9; 13; 14; 12; 23; 34; 22; 16; 17; 4; -5 ; -6; 5; 7; 0; 0; 0)
I want to convert values of F when it gets negative (in this case -6 and -5) till N (lets N=8)
so result would be F= (0; 0; 0; 0; 5; 7; 12; 11; 23; 32; 22; 10; 8; 0; 0; 0; 0; 0; 0; 0; 0; 0; 0; 6; 8; 9; 13; 14; 12; 23; 34; 22; 16; 17; 4; 0; 0; 0; 0; 0; 0; 0) how to do this?

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2014-8-6
F(F<0 & F>=-8)=0
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Azzi Abdelmalek
Azzi Abdelmalek 2014-8-6
编辑：Azzi Abdelmalek 2014-8-6
F= [0; 0; 0; 0; 5; 7; 12; 11; 23; 32; 22; 10; 8; -6 ;0; -8; 1; 4; 8; -5; 0; 0; 0; 6; 8; 9; 13; 14; 12; 23; 34; 22; 16; 17; 4; -5 ; -6; 5; 7; 0; 0; 0]
idx=find(F<0,1)
n=numel(F);
while ~isempty(idx)
F(idx:min(idx+7,n))=0;
idx=find(F'<0,1);
end

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更多回答（3 个）

Yu Jiang
Yu Jiang 2014-8-6
编辑：Yu Jiang 2014-8-6
while ~isempty(find(F<0))
id1 = find(F<0,1);
id2 = min(id1 + 7, length(F));
F(id1:id2) = 0;
end
Roger Stafford
Roger Stafford 2014-8-6
I am not sure what you mean in your remark "till N (lets N=8)". Do you mean that a maximum of N successive negative values in F are to be converted to 0 with all the possible remaining negative values, if any, unaffected? If so, the example you should have used ought to have demonstrated that behavior. In any case, here is code that would accomplish such a task:
F(find(F<0,N)) = 0;
  1 个评论
Sagar Dhage
Sagar Dhage 2014-8-6
N is next 8 values from -6 and -5. I want to convert all positive and negative values to 0 for this N=8 length. that is all values in old should be zero. your formula converts only negative.

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Roger Stafford
Roger Stafford 2014-8-6
I think I understand you now. How about this:
n = length(F);
for k = 1:n
if F(k) < 0
F(k:min(k+N-1,n)) = 0;
end
end

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