How to Convert vector elements to zero for certain N length when its values gets negative?
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I have a column vector F= (0; 0; 0; 0; 5; 7; 12; 11; 23; 32; 22; 10; 8; -6 0; -8; 1; 4; 8; -5; 0; 0; 0; 6; 8; 9; 13; 14; 12; 23; 34; 22; 16; 17; 4; -5 ; -6; 5; 7; 0; 0; 0)
I want to convert values of F when it gets negative (in this case -6 and -5) till N (lets N=8)
so result would be F= (0; 0; 0; 0; 5; 7; 12; 11; 23; 32; 22; 10; 8; 0; 0; 0; 0; 0; 0; 0; 0; 0; 0; 6; 8; 9; 13; 14; 12; 23; 34; 22; 16; 17; 4; 0; 0; 0; 0; 0; 0; 0) how to do this?
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Azzi Abdelmalek
2014-8-6
F(F<0 & F>=-8)=0
3 个评论
Azzi Abdelmalek
2014-8-6
编辑:Azzi Abdelmalek
2014-8-6
F= [0; 0; 0; 0; 5; 7; 12; 11; 23; 32; 22; 10; 8; -6 ;0; -8; 1; 4; 8; -5; 0; 0; 0; 6; 8; 9; 13; 14; 12; 23; 34; 22; 16; 17; 4; -5 ; -6; 5; 7; 0; 0; 0]
idx=find(F<0,1)
n=numel(F);
while ~isempty(idx)
F(idx:min(idx+7,n))=0;
idx=find(F'<0,1);
end
更多回答(3 个)
Roger Stafford
2014-8-6
I am not sure what you mean in your remark "till N (lets N=8)". Do you mean that a maximum of N successive negative values in F are to be converted to 0 with all the possible remaining negative values, if any, unaffected? If so, the example you should have used ought to have demonstrated that behavior. In any case, here is code that would accomplish such a task:
F(find(F<0,N)) = 0;
Roger Stafford
2014-8-6
I think I understand you now. How about this:
n = length(F);
for k = 1:n
if F(k) < 0
F(k:min(k+N-1,n)) = 0;
end
end
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