how can i get the nonzero value of Tdim{i}(1),while i have to start value of k=2:12?

Question

Deepesh Kumar Gupta 2021-10-6

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https://ww2.mathworks.cn/matlabcentral/answers/1468231-how-can-i-get-the-nonzero-value-of-tdim-i-1-while-i-have-to-start-value-of-k-2-12

回答： Ronit 2024-8-16

here is the result:

here is the main code:

% calculation of Rs
 theta=0:30*(pi/180):330*(pi/180);
x=ro*cos(theta);
y=ro*sin(theta);
y1=0;
rs=sqrt((x-e).^2+(y-y1).^2);
D=zeros(1000,12);
for i= 1:1000
    for j=1:12
D(i,j)=rs(j)./ri(i);
    end
end
D;
Rs=num2cell(D,2);
% Value of angle calculation
Tdimnot=(Thotspot-Tinf)./(Tref-Tinf);
alpha=atan2((y-y1),(x-e))*180/pi;
for k=1:12
if alpha(k)<0
    alpha(k)=360+alpha(k);
else
    alpha(k)= alpha(k);
end
end
for k=1:12
g(k)=alpha(k)*pi/180;
end
%  calculation of  1000 matrix of (12,12)
N=1000;
C=cell(1,N);
for i=1:N
    A=zeros(12,12);
for k=1:12
    for j=1:12
        if j==1
             A(k,j)=1./(Rs{i}(k))+Bi(i).*log(Rs{i}(k));
        else
        A(k,j)=((j-1)*((Rs{i}(k)).^(j-1)+(Rs{i}(k)).^(1-j))./(Rs{i}(k))+Bi(i)*((Rs{i}(k)).^(j-1)-(Rs{i}(k)).^(1-j)))* cos((j-1).*g(k));
        end
    end
end
C{i}=A;
end
% Calculation of Y
N=1000;
    Y=cell(1,N);
     E=zeros(12,1);
 for i=1:N
E=(C{i})\(B{i});    
Y{i}=E;
 end
 % calculation of each 12 dimensionless temperature at pheripheral
 N=1000;
  Tdim=cell(1,N);
 
 for i=1:N
     F=zeros(12,1);
 for k=2:12
    F(k,:)=1+(Y{i}(1)).*log(Rs{i}(k))+(Y{i}(k))*((Rs{i}(k)).^(k-1)-(Rs{i}(k)).^(k-1)).*cos((k-1).*g(k));
 end
 Tdim{i}=F;
 

Please help me in this ,i am trynig to find for last 4 days.

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Answer 1

Ronit 2024-8-16

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https://ww2.mathworks.cn/matlabcentral/answers/1468231-how-can-i-get-the-nonzero-value-of-tdim-i-1-while-i-have-to-start-value-of-k-2-12#answer_1499564

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Hello Deepesh,

I understand you are trying to ensure that ‘Tdim{i}(1)’ is nonzero, which can be achieved when its value is derived from the computations involving ’k=2:12’. In your existing code, ’Tdim{i}(1)’ is not explicitly calculated, which results in it being zero. To address this, we can compute ’Tdim{i}(1)’ as a function of the values computed for ’k=2:12’. One straightforward approach is to calculate ’Tdim{i}(1)’ as the average of these values, ensuring it is nonzero and representative of the data. Here's the revised code with this logic incorporated:

% calculation of each 12 dimensionless temperature at peripheral
Tdim = cell(1, N);
for i = 1:N
    F = zeros(12, 1);
    sum_k_values = 0; % Initialize sum of calculated values for k=2:12
    count_k = 0;      % Count the number of k values
    for k = 2:12
        F(k) = 1 + (Y{i}(1)) * log(Rs{i}(k)) + (Y{i}(k)) * ((Rs{i}(k)).^(k - 1) - (Rs{i}(k)).^(k - 1)) * cos((k - 1) * g(k));
        sum_k_values = sum_k_values + F(k); % Accumulate the sum
        count_k = count_k + 1;              % Increment the count
    end
    % Calculate Tdim{i}(1) as the average of the values from k=2:12
    F(1) = sum_k_values / count_k;
    Tdim{i} = F;
end