image quadrant one by one and move to next quadrant

Question

trinasha 2021-10-9

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1470521-image-quadrant-one-by-one-and-move-to-next-quadrant

评论： DGM 2022-3-4

Hello, I want to show mask one quadrant by one quadrant and take images. But the code is making on one quadrant and the two and three...Eventually all the quadrants are on. After comparing the intensities of the image, I want to move to that quadrant and divide it again by four, such as in images pdf attached. Can anyone please help me with this?

% function dimension = getquadrant(q1,q2,q3,q4)
clc
clear all
close all
%%load dmd
classname = 'alpV42x64';
tagname   = classname;
pseudoDLL = logical(0);
protofile = 'alpV42x64proto.m';
protofunc = @alpV42x64proto;
arch      = 'win64';
dllfile   = 'C:\Users\ReddyLabAdmin\Documents\MATLAB\alp4395.dll';
alplib('delete')
alplib('set', 'tag', tagname, 'classname', classname, ...
    'dllfile', dllfile, 'pseudoDLL', pseudoDLL, 'protofile', protofile, ...
    'protofunc', protofunc, 'arch', arch)
myapi = alpload();
mydev = alpdevice(myapi);
mydev.alloc();
%define the size of dmd
i = 1024;
j = 768;
dmd = zeros(i,j,'uint8');
[rows, columns, numColorChannels] = size(dmd)
numblocks = 2;
topRows = round(linspace(1, rows+1, numblocks + 1))
leftColumns = round(linspace(1, columns+1, numblocks + 1))
%show mask and capture image
for row = 1 : length(topRows) - 1
    row1 = topRows(row);
    row2 = topRows(row + 1) - 1;
    for col = 1 : length(leftColumns) - 1
        col1 = leftColumns(col);
        col2 = leftColumns(col + 1) - 1;
        
        dmd(row1 : row2, col1 : col2, :) = 255;
        mydev.put(dmd);
        myimage1 = captureimage();
        %imwrite(myimage1,'r_row%d%dcolumn%d%d.jpg,row1, row2, col1, col2');
        mydev.stop();
    end
end
% %q1
% dmd = zeros(i,j,'uint8'); 
% q1 = 1:j/2,1:i/2;
% dmd(q1) = 255;
% mydev.put(dmd);
% myimage1 = captureimage();
% imwrite(myimage1,'Q1.jpg');
% mydev.stop();
% %q2
% dmd = zeros(i,j,'uint8'); 
% q2 = j/2:j,1:i/2;
% dmd(q2) = 255;
% mydev.put(dmd);
% myimage2 = captureimage();
% imwrite(myimage2,'Q2.jpg');
% mydev.stop();
% %q3
% dmd = zeros(i,j,'uint8'); 
% q3 = 1:j/2,i/2:i;
% dmd(q3) = 255;
% mydev.put(dmd);
% myimage3 = captureimage();
% imwrite(myimage3,'Q3.jpg');
% mydev.stop();
% %q4
% dmd = zeros(i,j,'uint8');  
% q4 = j/2:j,i/2:i;
% dmd(q4) = 255;
% mydev.put(dmd);
% myimage4 = captureimage();
% imwrite(myimage4,'Q4.jpg');
% mydev.stop();
maximumintensity = calculatemaximum(myimage1,myimage2,myimage3,myimage4);
% if maximumintensity == meanIntensityValue1
%     dimension = size(q1);
%  else if maximumintensity == meanIntensityValue2
%         dimension = size(q2);
%         
%  else if maximumintensity == meanIntensityValue3
%         dimension = size(q3);
%        
%  else maximumintensity == meanIntensityValue4
%         dimension = size(q4);
% end

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DGM 2021-10-9

编辑：DGM 2021-10-9

What should happen when the image geometry is not integer-divisible by [8 8]?

EDIT: Or is the image always the 256x256 DMD mask?

trinasha 2021-10-10

I just want the mask(1024*768) to be divided in quadrant and it is divisible up to 256*256.

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Answer 1

DGM 2021-10-10

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1470521-image-quadrant-one-by-one-and-move-to-next-quadrant#answer_805276

编辑：DGM 2021-10-10

在 MATLAB Online 中打开

This should be a start

s = [768 1024];

% generate three masks that can be transformed and combined

% to create the desired masks

m4 = false(s);

m4(1:s(1)/2,1:s(2)/2) = true;

squaresize = s/4;

xx = mod(0:(s(2)-1),squaresize(2)*2)<squaresize(2);

yy = mod(0:(s(1)-1),squaresize(1)*2)<squaresize(1);

m16 = xx & yy';

squaresize = s/8;

xx = mod(0:(s(2)-1),squaresize(2)*2)<squaresize(2);

yy = mod(0:(s(1)-1),squaresize(1)*2)<squaresize(1);

m64 = xx & yy';

% just display them for sake clarifying the example

subplot(1,3,1)

imshow(m4)

subplot(1,3,2)

imshow(m16)

subplot(1,3,3)

imshow(m64)

This is an example of how this can be used to generate all the masks:

clf
for a = 1:4
    thismask = xfmask(m4,a);
    % do something with the mask ...
    dothings(thismask);
end
for a = 1:4
    tm4 = xfmask(m4,a);
    for b = 1:4
        thismask = tm4 & xfmask(m16,b);
        % do something with the mask ...
        dothings(thismask);
    end
end
for a = 1:4
    tm4 = xfmask(m4,a);
    for b = 1:4
        tm16 = xfmask(m16,b);
        for c = 1:4
            thismask = tm4 & tm16 & xfmask(m64,c);
            % do something with the mask ...
            dothings(thismask);
        end
    end
end
% placeholder task function
function dothings(m)
    imshow(m)
    pause(0.1)
end
% convenience function to flip masks
function y = xfmask(x,k)
    switch k
        case 1
            y = x;
        case 2
            y = fliplr(x);
        case 3
            y = flipud(x);
        case 4
            y = rot90(x,2);
        otherwise
            error('k must be between 1 and 4')
    end
end

This will just show the masks in sequence. Bear in mind that if the equipment controller is expecting a uint8-scaled image, you can just use im2uint8(thismask) to convert it.

I bet there's some elegant way of doing this, but this works.

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DGM 2021-10-12

在 MATLAB Online 中打开

Oh I missed that. Maybe this is a bit closer.

s = [768 1024];
% generate three masks that can be transformed and combined
% to create the desired masks
m4 = false(s);
m4(1:s(1)/2,1:s(2)/2) = true;
squaresize = s/4;
xx = mod(0:(s(2)-1),squaresize(2)*2)<squaresize(2);
yy = mod(0:(s(1)-1),squaresize(1)*2)<squaresize(1);
m16 = xx & yy';
squaresize = s/8;
xx = mod(0:(s(2)-1),squaresize(2)*2)<squaresize(2);
yy = mod(0:(s(1)-1),squaresize(1)*2)<squaresize(1);
m64 = xx & yy';
% build masks and test
intvector = zeros(4,1);
for a = 1:4
    thismask = xfmask(m4,a);
    % do something with the mask ...
    intvector(a) = dothings2(thismask);
end
[maxinta maxidxa] = max(intvector); % index of the image with highest intensity
tm4 = xfmask(m4,maxidxa);
for b = 1:4
    thismask = tm4 & xfmask(m16,b);
    % do something with the mask ...
    intvector(b) = dothings2(thismask);
end
[maxintb maxidxb] = max(intvector);
tm16 = xfmask(m16,maxidxb);
for c = 1:4
    thismask = tm4 & tm16 & xfmask(m64,c);
    % do something with the mask ...
    intvector(c) = dothings2(thismask);
end
[maxintc maxidxc] = max(intvector); % if this value is still needed
% placeholder task function
function fint = dothings2(m)
    % this is just visualization for demonstration
    imshow(1-m)
    pause(0.1)
    
    % other tasks would be done here, for example:
    % clear the DMD (if that's necessary)
    % set DMD to the current mask
    % capture the image
    % get image intensity
    fint = rand(1); % placeholder intensity for this frame
end
% convenience function to flip masks
function y = xfmask(x,k)
    switch k
        case 1
            y = x;
        case 2
            y = fliplr(x);
        case 3
            y = flipud(x);
        case 4
            y = rot90(x,2);
        otherwise
            error('k must be between 1 and 4')
    end
end

Of course, this isn't complete. I don't have the hardware, so I'm not inclined to write the code for the parts I can't test. I'm not sure why it seems like your masks keep adding up. Does the DMD need to be explicitly cleared?

I'm not sure what the outputs need to be. So far, all this does is generate masks and compare intensities. None of the captured images are saved, only the intensities and indices of the three frames with highest intensity. The indexing scheme is [NW NE SW SE].

trinasha 2022-3-1

pixel position.PNG

I got it this way (attached image)

DGM 2022-3-4

Oh. So the intensity peak within the mask. ... but is the rest of it doing what you needed?

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image quadrant one by one and move to next quadrant

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