Find unique combinations of double and character elements

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Maria
Maria 2014-8-10
回答： Yu Jiang 2014-8-10
I have a cell type variable with 3 columns and 500000 rows, here is an example:
c1 c2 c3
A={1994 'AACE' 2071
1994 'AACE' 30677
1994 'AAC' 1541
1994 'AAC' 2027
1994 'AAC' 7843}
I am applying the following code:
%Unique combinations of c1 and c2
[y,~,ind] = unique([num2str(c1) c2], 'rows'); %Problem
%Count occurences
c = accumarray(ind,1);
%Final variable
F = [y c];
But it gives me an error in the first row, because I am trying to find unique combinations of 'double' and 'char' elements. Can someone help me? Thanks
  2 个评论
Yu Jiang
Yu Jiang 2014-8-10
Hi Maria
It would be easier to help you if you could show the exact error message.
-Yu
Maria
Maria 2014-8-10
Hi Yu,
it gives this error: Error using horzcat Dimensions of matrices being concatenated are not consistent.

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2014-8-10
编辑：Azzi Abdelmalek 2014-8-10
A={1994 'AACE' 2071
1994 'AACE' 30677
1994 'AAC' 1541
1994 'AAC' 2027
1994 'AAC' 7843};
c12=cellfun(@(x,y) [num2str(x) y],A(:,1),A(:,2),'un',0);
[y,ii,ind] = unique(c12) %Problem
c = accumarray(ind,1);
F = [A(ii,:) num2cell(c)]

更多回答（2 个）

Andrei Bobrov
Andrei Bobrov 2014-8-10
[y0,~,ii] = unique(A(:,2));
[y,~,i0] = unique([cell2mat(A(:,1)),ii],'rows')
F = [num2cell(y(:,1)),y0,num2cell(accumarray(i0,1))];
  1 个评论
Maria
Maria 2014-8-10
It gives the following error: Error using horzcat Dimensions of matrices being concatenated are not consistent.

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Yu Jiang
Yu Jiang 2014-8-10
I believe both the answers by Andrei Bobrov and Azzi Abdelmalek are correct. The error message should be caused by your original definition of A. If you create A exactly as Azzi does, then there should be no problem.
By the way, they both use the function cellfun, which is very convenient for cell operations. More details can be found here (Documentation) .

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