Attempted to access y(2); index out of bounds because numel(y)=1. Error in ==> dft at 9 z(k)=y(k)+y(i)(exp(-i2pi/n)^ki);

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vinay teja 2014-8-13

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编辑： Andrei Bobrov 2014-8-13

this is the code i'm working out but i'm getting some errors pls help in in solving this...

clc 
clear all
close all
x=input('enter x:')
n=length(x)
for k=1:n
    y(k)=0
    for i=1:n
        z(k)=y(k)+y(i)*(exp(-i*2*pi/n)^k*i);
    end
end
z

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Answer 1

Julia 2014-8-13

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编辑：Julia 2014-8-13

在 MATLAB Online 中打开

Hi,

You do not define the size of y (I guess the same size as x). So you get for k=1 y(1) but try to access y(2), y(3), ... , y(n) in the second for loop. k stays 1 while i increases. Preallocating the size of y should solve your problem.

>> x = [1 2 3 4]
x =
       1     2     3     4
>> y=zeros(1,length(x))
y =
       0     0     0     0

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Attempted to access y(2); index out of bounds because numel(y)=1. Error in ==> dft at 9 z(k)=y(k)+y(i)(exp(-i2pi/n)^ki);

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Attempted to access y(2); index out of bounds because numel(y)=1. Error in ==> dft at 9 z(k)=y(k)+​y(i)*(exp(​-i*2*pi/n)​^k*i);

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Attempted to access y(2); index out of bounds because numel(y)=1. Error in ==> dft at 9 z(k)=y(k)+y(i)(exp(-i2pi/n)^ki);

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