Structure problem? How to write a loop to solve it?

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tabw 2014-8-14

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https://ww2.mathworks.cn/matlabcentral/answers/150826-structure-problem-how-to-write-a-loop-to-solve-it

评论： tabw 2014-8-17

I have a 1x N Structure called Structure.data

Structure(1).data and Structure(i).data have different dimensions.

I want Structure(1).data minus Structure(2:i).data;

tempcon=(abs(bsxfun(@minus,Structure(q).result',Structure(l).result)));

and see those value from subtraction contains the certain value.

If it is, combine it to new Structure and use the new Structure to do the subtraction

and so on.

In short, Structure(1)-Structure(2)= true; Structure(1)=Structure(1)+Structure(2) and use Structure (1) -Structure(3) ...until Structure(i) after combine the useful Structure into Structure(1) Store it.

And use the left Structure to subtract any Structure. group it again

until all the Structures are grouped..

How to write a loop about this?

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tabw 2014-8-14

编辑：tabw 2014-8-14

在 MATLAB Online 中打开

    number=0;
    abc=[];
    abcd=[];
    N=300;
    k=1;
    q=1;
    l=q+1;
    v=1:272;
    constant=1;
    control=[0];
    testvalue=[0];
    Structure(N).result=zeros(15);
    Cell=im2bw(imread('Ims.png')); % convert input image into binary image
    [R C]=size(Cell);
    temp1=[];
     num=0;
     result=[];
     counter=1;
____________________________________________________________
    for i= 1:R
        for j=1:C
    Cell(j,i);
    if (find(Cell(j,i))==1)  % find all the white pixel on image
        temp=[i j];
        temp1=cat(2,temp1,temp); % store all the white pixel coordinate into array
         num=num+1;
    end
        end
    end
__________________________________________________________________________________
    a=temp1(counter); % convert coordinate back to (m,n) format
    b=temp1(counter+1);% convert coordinate back to (m,n) format
    while (counter<=(size(temp1,2)-2))
    j=(a-1)*300+b;
    result=cat(2,result,j);
    c=temp1(counter+2);  %Next a coordinate
    d=temp1(counter+3);  % Next b coordinate
    x=((c-a)^2+(d-b)^2)^(1/2); % test the next (a,b) which is connected to current (a,b)
    if (x <= (2)^(1/2))  % if it is connected, go on to store coordinate into result
    else
            temp00=[];
            temp00=result;
            Structure(k).result=temp00; % store a set connected pixel coordinate into Structure
            k=k+1;
            result=[];
            number=number+1;
        end 
    counter=counter+2;  
    a=temp1(counter);  % Next a 
    b=temp1(counter+1); % Next b
    end
__________________________________________________________________________
   while (l<number) 
    tempcon=(abs(bsxfun(@minus,Structure(q).result',Structure(l).result)));
    ans=(tempcon==300);
    Tr=find(ans==1);
    if (Tr>=1)
    Structure(q).result=struct('object',[Structure(q).result Structure(l).result]); 
    Structure(q).result=Structure(q).result.object;
    Structure(l).result=[];
    control=[control,q,l];

end

The last part is not completed.

Q1. )

tempcon=(abs(bsxfun(@minus,Structure(q).result',Structure(l).result)));
    ans=(tempcon==300); % check any value contains 300

Q2.)

    Structure(q).result=struct('object',[Structure(q).result Structure(l).result]); 
        Structure(q).result=Structure(q).result.object;

Actually, I am finding the connected object.

Image Analyst 2014-8-14

I didn't go over this in detail, but are you trying to do connected components labeling, like what bwlabel() or bwconncomp() does?

tabw 2014-8-17

Exactly.

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Structure problem? How to write a loop to solve it?

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