low speed of 'ismember' function

hi. in my code there is a for loop like the following:
for i=1:n
N=find(~ismember(Vector1,Vector2))
do something...
end
This loop is repeated several thousand times. 'ismember' function is very slow. So that most of the runtime for 'ismember' function lost. Is there any alternative to this?

回答(3 个)

Johan Löfberg
Johan Löfberg 2014-8-29

0 个投票

If data is sorted, using ismembc could be a quick fix.

2 个评论

No. This loop used for programming the Traveling Salesman Problem. this vectors is not sorted and can't be like that.
Then I would scratch ismember and do sort+ismembc (ismember contains a lot of overhead. look into it and you will see that it basically does sort+ismembc once all data is checked etc)

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Depending on your data, you might try to code your own function avoiding some conditions and calls to sub-functions within the ismember function.
You can take a look at ismember code with:
type ismember
and try to make it easier.

3 个评论

this is my code:
for k=1:nAnt
ant(k).Tour=randi([1,nCity],1,1);
end
for i=2:nCity
for k=1:nAnt
N=find(~ismember(1:nCity,ant(k).Tour));
% do somthing
end
end
The way you use ismember() seems to be inefficient. You are going to be processing similar things over and over. You could instead loop through the variable of interest, do an exhaustive search, save that somewhere and then %do something based on those results.
I just do not understand. What is your suggestion? Please change the code according to your suggestion.

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Hi,
does "Vector1" and "Vector2" changes in every iteration? Often you see something like
for i=1:n
v = ismember(x(i), y);
% do something
end
which can be changed to
vAll = ismember(x, y);
for i=1:n
% now do something with vAll(i)
end
Titus

1 个评论

this is my code:
for k=1:nAnt
ant(k).Tour=randi([1,nCity],1,1);
end
for i=2:nCity
for k=1:nAnt
N=find(~ismember(1:nCity,ant(k).Tour));
% do somthing
end
end

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2014-8-29

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