Append column given a 'year' condition

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Maria
Maria 2014-9-2
评论： Maria 2014-9-2
I have a cell type variable A with 30000 rows and 29 columns, for example:
b1 *b2* b3 b4 b5 b6 b7 ...
A={7 1999 28,14 1388 33 78 39021
8 2002 44,44 150 4 56 60012
12 2002 54,46 100 21 49 40701
13 1998 46,41 189 22 44 30901...}.
Column b2 gives different years. I am trying to a ppend a new column that, for example, gives 1 if the year in b2 is after 2000 and 0 if the year in b2 is before 2000 . For instance in this example I would get:
b1 *b2* b3 b4 b5 b6 b7 ... b30
A={7 1999 28,14 1388 33 78 39021 0
8 2002 44,44 150 4 56 60012 1
12 2002 54,46 100 21 49 40701 1
13 1998 46,41 189 22 44 30901... 0}.
Can someone help me please? Thank you.

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采纳的回答

Guillaume
Guillaume 2014-9-2
编辑：Guillaume 2014-9-2
A(:, end+1) = num2cell([A{:, 2}] >= 2000);
  2 个评论
Guillaume
Guillaume 2014-9-2
However, if you only have numbers in your cell array, why aren't you using a matrix? It makes manipulation much easier
A = cell2mat(A);
A(:, end+1) = A(:, 2) >= 2000;

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更多回答（1 个）

José-Luis
José-Luis 2014-9-2
A = num2cell(1995 + randi(10,[20 1]));
A(:,end+1) = num2cell( cell2mat(A) >= 2000)

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