It is a curl error or I am using it wrong?
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Hi, I just want to graph the curl of this vector field:
F(x,y)=-2x ay % just have y direction not x.
Manually the curl gives me: -2 az, but when using the curl function in matlab it gives me -1 (a constant plane in z=-1), why? It suppose to give me a constant plane in z=-2.
code:
[x,y]=meshgrid(0:0.1:5, 0:0.1:5);
Fx=0.*x;
Fy=-2.*x;
rot=curl(x,y,Fx,Fy);
mesh(x,y,rot)
采纳的回答
Harshad Deshmane
2014-9-29
You might be using the wrong output of the “curl” function to create the mesh plot. Calling “curl” with only one output argument gives you the curl angular velocity and not the curl z-component, which is what you need to get the mesh plot. You can refer to the documentation page for “ curl " for more information.
I suggest making the following changes:
>> [curlz, cav] = curl (x, y, Fx, Fy);
>> mesh (x, y, curlz)
I think this should resolve your issue.
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