How to find the location of the first cell which contains a specific value in an array?

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zy 2014-9-9

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评论： zy 2014-9-11

I have an array, all the cells are either with value 0 or value 1.

For each row, I need to find the location in form of (row, column) for the fist cell with value 1 in this row, and the location for the last cell with value 1 in this same row.

Then I will repeat this to all the other rows of the matrix.

I used double for loop, but I did succeed in storing the cell locations.

Can anyone help me?

Thank you.

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per isakson 2014-9-9

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编辑：per isakson 2014-9-10

在 MATLAB Online 中打开

I'm not sure what you mean by "cell". Hint:

    m = randi( [0,1], [12,12] );
    n = nan( 2, 12 );
    for jj = 1 : size( m, 2 )
        n(:,jj) = [ find( m(:,jj)==1, 1, 'first' )
                    find( m(:,jj)==1, 1, 'last'  ) ];
    end

I'm not sure how it behaves if there is no value, 1, in a column.

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zy 2014-9-10

Ok, I will read the FAQ for better understanding of those terminologies, thank you.

zy 2014-9-11

Yes, per Isakson, it works, thank you very much. It helps me a lot.

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