how can find size of this objects in a binary image?

29 次查看（过去 30 天）
sara
sara 2014-9-24
编辑： Image Analyst 2021-10-23
hi I have a binary image and it has some objects...how can find size of this objects??Is there any toolbox in matlab for this??

请先登录，再回答此问题。

采纳的回答

Meshooo
Meshooo 2014-9-25
编辑：Meshooo 2014-9-25
There are many ways to do that. One easy way is to use nnz (Number of nonzero matrix elements).
So if your image is I, then:
I = im2bw (I); %be sure that your image is binary
Total_White_Pixels = nnz(I); % total area based on number of white pixels
Hope that helps you.
  3 个评论
显示 1更早的评论
Image Analyst
Image Analyst 2021-10-23
编辑：Image Analyst 2021-10-23
@sylvester Fok, the units are "pixels" since nnz() gives a count of elements with non-zero values in an array. If you have the area of a pixel in real world units, like it's 5 square meters per pixel, then you can multiply by that spatial calibration factor, like I do in the attached demo.
Note that this answer just gives the area of all blobs added together, not of single blobs like I showed in my answer below. Essentially:
mask = grayImage > 128; % Create a logical binary image.
props = regionprops(mask, 'Area'); % Find areas of each blob and put into a structure.
allAreas = [props.Area]
Be sure to run my Image Segmentation Tutorial.
Image Analyst's File Exchange

请先登录，再进行评论。

更多回答（4 个）

Meshooo
Meshooo 2014-9-25
编辑：Meshooo 2014-9-25
You can do it in few steps. If your input image is I then:
%Step 1: Label each object using the following code.
I = im2bw(I); % be sure your image is binary
L = bwlabel(I); % label each object
%Step 2: see the label of each object
s = regionprops(L, 'Centroid');
imshow(I)
hold on
for k = 1:numel(s)
c = s(k).Centroid;
text(c(1), c(2), sprintf('%d', k), ...
'HorizontalAlignment', 'center', ...
'VerticalAlignment', 'middle');
end
hold off
% Step 3: find the area of the object you want using its label
Obj = (L == 1) % 1 is the label number of the first object.
figure, imshow(Obj);
Area = regionprops(Obj,'Area') % the answer
Now, for example if you want to find the area of object number 3, the just change number 1 to 3.
Obj = (L == 3) where 3 is the label number of the third object.
Area is the number of pixels in the object.
Hope that will help.
Matt J
Matt J 2014-9-24
How about,
regionprops(...,'Area')
Image Analyst
Image Analyst 2014-9-24
编辑：Image Analyst 2021-10-23
Of course sara. I thought you've already run across my image segmentation tutorial by now. Run it here http://www.mathworks.com/matlabcentral/fileexchange/?term=authorid%3A31862, replacing the coin image with yours. It will tell you the areas, centroids, bounding boxes, coordinates of the perimeter, etc.
Basically, it's
mask = grayImage > 128; % Create a logical binary image.
props = regionprops(mask, 'Area'); % Find areas of each blob and put into a structure.
allAreas = [props.Area]
sara
sara 2014-9-25
编辑：sara 2014-9-25
thanks Image Analyst and Meshooo Matt
I searched and tried this codes befor... but I want to know the size of an object in this image..I don't want to obtain the largest or smallest objects of this image..I want to know just the size of white object.. for simples of this question we can assume that we just have one object in this image...I hope I could explain my question clearly ...I have tow images that are very similar to each other and I want to chose the image that my goal object is larger in it...thanks

类别

在 Help Center 和 File Exchange 中查找有关 Get Started with Image Processing Toolbox 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by