fit function does not work correctly
52 次查看(过去 30 天)
显示 更早的评论
I wanted to test a custom fit with a simple function ( cos(3.5t) ) and so I made the following code. But when I plot, the resultant fit doesn't follow the function at all.
t = [0:0.01:6]';
%Test with a cosinus function
y = cos(t*3.5);
%Create the fit type
fitmodel = @(a, x) cos(a.*x);
%Fit the curve
fitted = fit(t, y, fitmodel, 'TolX', 1E-15);
%Plot the curve and the fit
figure
plot(t, y, 'b.')
hold on
plot(t, fitted(t), 'r-')
hold off
1 个评论
Mathieu NOE
2021-10-11
hi
look at the warning
Warning: Start point not provided, choosing random start point.
some fitting functions are (very) sensitive to initial conditions . you should be able to give a better start point
采纳的回答
John D'Errico
2021-10-11
编辑:John D'Errico
2021-10-11
I wrote a long question (and answer) just yesterday, that goes into depth on the why and how to solve this.
The point is, that you need to provide better starting values for the solver.
When you alow it to use its own (random) start point, for this cleass of model, you will often find a poor fit results.
t = [0:0.01:6]';
%Test with a cosinus function
y = cos(t*3.5);
%Create the fit type
fitmodel = @(a, x) cos(a.*x);
%Fit the curve
fitted = fit(t, y, fitmodel, 'TolX', 1E-15)
Here, a is estimated as less than 1, clearly a poor estimate. Even if I provide a start point of 2 for a, it gets it wrong.
fitted = fit(t, y, fitmodel, 'TolX', 1E-15, 'start',2)
try a little larger?
fitted = fit(t, y, fitmodel, 'TolX', 1E-15, 'start',3)
And that did it. I needed to start the solver out inside the basin of attraction before it will find the global solution.
For much more depth on the concepts here, read the question and answers I posted in that link.
0 个评论
更多回答(2 个)
Chunru
2021-10-11
If the StartPoint is good enough, you can get the correct fitting.
t = [0:0.01:6]';
%Test with a cosinus function
y = cos(t*3.5);
%Create the fit type
fitmodel = @(a, x) cos(a.*x);
%Fit the curve
fitted = fit(t, y, fitmodel, 'TolX', 1E-15, 'StartPoint', 3);
%Plot the curve and the fit
figure
plot(t, y, 'b.')
hold on
plot(t, fitted(t), 'r-')
hold off
0 个评论
Matt J
2021-10-11
编辑:Matt J
2021-10-11
You shouldn't use a custom model when one is unnecessary. It is an important advantage to use one of the built-in models when possible, because the fitting algorithm can do smarter things, including the automatic generation of a StartPoint. Here, you can use 'sin1' or 'fourier1' with appropriate bounds:
t = [0:0.01:6]';
%Test with a cosinus function
y = cos(t*3.5);
opts=fitoptions('sin1','Lower',[1 -inf, pi/2],'Upper',[1 +inf pi/2]);
%Fit the curve
fitted = fit(t, y, 'sin1',opts);
%Plot the curve and the fit
figure
plot(t, y, 'b.')
hold on
plot(t, fitted(t), 'r-')
hold off
0 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Regression 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!