Intergrating the data using a scalar value

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Vishnuvardhan Naidu Tanga 2021-10-12

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评论： Mathieu NOE 2021-10-12

采纳的回答： Mathieu NOE

Abb76at104.xlsx

Hello,

I am trying to do integration of a excel data. When I try to do that I am getting an error as follows:

Error using cumtrapz (line 51)

Dimension argument must be a positive integer scalar within indexing range.

Please can someone help me in solving that .

My code:

X1 = xlsread('Abb76at104.xlsx','A1:A63');

Y1 = xlsread('Abb76at104.xlsx','B1:B63');

V = 40.020;

A1 = pi*(X1).^2;

Q1 = A1.*Y1;

Int1 = cumtrapz(A1, V);

X2 = xlsread('Abb76at104.xlsx','A64:A130');

Y2 = xlsread('Abb76at104.xlsx','B64:B130');

A2 = pi*(X2).^2;

Q2 = (A2).*40.02;

Int2 = cumtrapz(A2, V);

Thanks in advance.

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采纳的回答

Mathieu NOE 2021-10-12

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hello

see the doc for cumtrapz

I believe you simply put the arguments in the wrong order

it must be

Int1 = cumtrapz(V,A1);

and

Int2 = cumtrapz(V,A2);

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Vishnuvardhan Naidu Tanga 2021-10-12

Thank you once again for sorting the thing out. Have a nice day.

Mathieu NOE 2021-10-12

my pleasure (again) !

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