How to tell loop how many values to skip?

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MC3105
MC3105 2014-9-28
编辑： MC3105 2014-9-28
Hello everyone!
I want to create a loop similar to:
t=1:24:300
BUT I don't want the loop to skip 24 values after every run-through. After each run-through I want to tell the loop exactly how many values it should skip.
For example: The first run-through should be from 1:24, the second should be from 25:30, the third should be from 31:50.... and the last one from 277:300.
Is this possible in matlab?
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José-Luis
José-Luis 2014-9-28
编辑：José-Luis 2014-9-28
Do you know the values beforehand or will they be calculated inside the loop? Also, I don't really understand what you mean by 25:30, 31:50, etc...
MC3105
MC3105 2014-9-28
I just found a solution :)
I can do
t=1:s:300
then I can calculate the number of steps to skip within the loop :)

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Star Strider
Star Strider 2014-9-28
This seems to do what you want:
X = linspace(0, 10, 300); % Create Data Vector
t = [0 24 30 50 276 300]; % Partition Index Vector
for k1 = 1:length(t)-1
Y{k1} = X(t(k1)+1:t(k1+1));
end
The cell array ‘Y’ has your partitioned sections from vector ‘X’. Create ‘t’ to be whatever values you want. I used the numbers you defined in your Question in this example.
  1 个评论
MC3105
MC3105 2014-9-28
编辑：MC3105 2014-9-28
unfortunately i don't know beforehand how my intervals will look like..
but I just found my solution: it's possible to do t=1:s:24 and then calculate the number of steps that the loop should skip before the next run-through as s within my loop :)

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更多回答（1 个）

Marc
Marc 2014-9-28
It is definitely possible but your logic is not very clear. Since you are choosing odd intervals, is there some underlying reason for 1 thru 24 followed by 25 thru 30, etc. etc.
You could use if/else-if/else or switch/case or while but we would need to have some condition met to move to the next run, and so on.

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