find max of a vector between two indice
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Hi, I want a code to find the maximum number between two indice of a vector.
I have an indice vector and a data vector . For example my indice vector is :
A=[3 7 13]
and my data vector is:
B=[-5 3 -8 1 -7 2 -9 3 6 2 7 9 -4 2 6]
now the max number between indices 3 and 7 of vector B is number "2" .
and the max number between indices 7 and 13 of vector B is number "9".
So the output should be like a vector named C as follows:
C=[2 9]
I've been thinking on this for hours but haven't found any solution yet :(
Tnx in advance.
采纳的回答
Lucas García
2011-9-12
>> C = arrayfun(@(x) max(B(A(x):A(x+1))),1:length(A)-1)
C =
2 9
1 个评论
Andrei Bobrov
2011-9-12
Hi friends!
My part
C = cellfun(@max,mat2cell(B(A(1):A(end)),1,diff(A)+[1 0]))
更多回答(3 个)
Sean de Wolski
2011-9-12
Easiest, and likely fastest way is just to use a for-loop:
A=[3 7 13];
B=[-5 3 -8 1 -7 2 -9 3 6 2 7 9 -4 2 6];
nmax = length(A)-1;
maxes = zeros(1,nmax);
for ii = 1:nmax
maxes(ii) = max(B(A(ii):A(ii+1)));
end
TIMINGS Mac 2009b
A=[3 7 13];
B=[-5 3 -8 1 -7 2 -9 3 6 2 7 9 -4 2 6];
t1 = 0;
t2 = 0;
for ii = 1:100
tic
nmax = length(A)-1;
maxes = zeros(1,nmax);
for ii = 1:nmax
maxes(ii) = max(B(A(ii):A(ii+1)));
end
t1 = t1+toc;
tic
C = arrayfun(@(x) max(B(A(x):A(x+1))),1:length(A)-1);
t2 = t2+toc;
end
t2/t1
ans = 25.029
arrayfun takes about 25x longer on my system
3 个评论
Sean de Wolski
2011-9-12
I would write a new specific function that accepts A,B and spits out an answer. Then call it from where we need prettiness.
Fangjun Jiang
2011-9-12
A=[3 7 13];
B=[-5 3 -8 1 -7 2 -9 3 6 2 7 9 -4 2 6];
C=zeros(1,numel(A)-1)
for k=1:numel(A)-1
C(k)=max(B(A(k):A(k+1)));
end
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