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approximating pi with taylor series expansion to the 10,000th term

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charlotte davis 2014-10-2

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编辑： Mischa Kim 2014-10-2

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This was my code: I=0

while (I<10000)

I=((-1)^I)/(2*I+1)

end

x=4*I

so when I do that the answer shows as

x =

NaN + NaNi

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Mischa Kim 2014-10-2

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编辑：Mischa Kim 2014-10-2

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charlotte, you are almost there:

 l = 1;
 for ii = 1:10000
    l = l + ((-1)^ii)/(2*ii + 1);
 end
 x = 4*l;

If the number of iterations (series terms) is know, use a for-loop
ii is the loop index, l is the approximation to pi/4

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