How to exclude min and max only once in a if statement?

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Jason
Jason 2014-10-7
编辑： José-Luis 2014-10-7
Can anyone please tell me how when using an if statement and taking the mean of a vector of any size. when I take the mean of the vector I am asked if the vector has more than 6 elements exclude the min and max. But if the min or max occurs more than once only exclude it once.
so far I have ...
function ave = improvedMean(V1)
n = length(V1)
if n>0 %%n<= 5
sum(V1) / n
elseif n >= 6
((sum(v1)-((min(v1)+(max(v1))) / (n-2)
I'm not sure where to go from there..

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采纳的回答

Mohammad Abouali
Mohammad Abouali 2014-10-7
What you did was correct. Just add an "end" at the end of your code and change
if n>0 %%n<= 5
to
if n>0 && n<= 5

更多回答（2 个）

the cyclist
the cyclist 2014-10-7
编辑：the cyclist 2014-10-7
function ave = improvedMean(V1)
n = length(V1)
if n <= 5
ave = sum(V1) / n
else
ave = (sum(V1)-(min(V1)+max(V1))) / (n-2)
end
José-Luis
José-Luis 2014-10-7
编辑：José-Luis 2014-10-7
Can be done with logical indexing:
Edited to take into account the six elements limit
a = randi(10,[5,1]);
n = size(a,1);
s = sort(a);
cond = diff(s);
idx = ones(n,1);
idx([1 end]) = ~cond([1 end]) .* n < 6;
your_mean = mean(s(logical(idx)));
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