could anyone help me how to pair the numbers in the desired manner as shown below
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A=1:16
R = reshape(A,4,[])
After executing the above command results in
R =
1 5 9 13
2 6 10 14
3 7 11 15
4 8 12 16
Now I want to group the numbers in the desired manner
1 2 3 4 5 6 7 8
12 11 10 9 16 15 14 13
Could anyone please help me on this.
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采纳的回答
Dyuman Joshi
2021-11-2
This looks a quite a unique manner. Anyways, try this
A=1:16;
R = reshape(A,4,[]);
[R(:,1)' R(:,2)'; flip(R(:,3))' flip(R(:,4))']
3 个评论
Dyuman Joshi
2021-11-3
编辑:Dyuman Joshi
2021-11-3
I am not sure what you mean by combining all into a single code, so here's my approach -
for i=[3 4 6 9 12]
z=1:4*i;
y=reshape(z,[],4);
R=[y(:,1)' y(:,2)'; flip(y(:,3))' flip(y(:,4))']
end
Here R will be modified in each iteration. You can modify the code according to however you want to proceed.
更多回答(1 个)
Yongjian Feng
2021-11-2
reshape(A, 8, 2)'
2 个评论
Yongjian Feng
2021-11-2
Whoops. Didn't pay attention to the order of the second row.
Then we need to use flip most likely.
A=1:16
R = reshape(A,4,[]);
R(:, 3) = flip(R(:, 3));
R(:, 4) = flip(R(:, 4));
ret = reshape(R, 8, 2)'
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