Question about a:h:b
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I have a quick question:
if a=1, h=1, b=5, then a:h:b will turn out to be [1 2 3 4 5]
However, if I want to do backward: b:h:a
it turns out to be a 1*0 empty row vector
is there any possibility we can still equally distribute the space and make b:h:a turns out to be [5 4 3 2 1]?
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