Taking Average of Nonzero Elements

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Imam
Imam 2014-10-17
评论： Imam 2014-10-17
Hi everyone,
I have got 2 questions, I hope someone can help me.
The first one is, I have a matrix A where
A = 1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
Then I apply the following
A = A>6 & A<11
[r,c,v] = find(A)
Doing that in the end I will have the information of indices that belong to those elements fulfilling the condition A>5 & A<12 in vectors r and c. Now I have another matrix B of the same dimensions as A.
B = 54 32 13 5
1 10 45 24
4 44 2 15
66 26 17 89
I want to choose only elements of B having the same indices as the elements in A that fulfilled the previous condition, leaving the other elements as zero. But if a row of B doesn't have such element matching what was mentioned above then it's truncated. So in the end I will have
result = 0 0 45 24
4 44 0 0
My last problem is simply how to take the average value on each element of matrix 'result' ignoring zeros, so what I will get is
mean = 34.5
24
I will really appreciate any help. Thanks in advance.

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采纳的回答

Matt J
Matt J 2014-10-17
编辑：Matt J 2014-10-17
L=(A>6 & A<11);
means=sum(B.*L,2)./sum(L,2);
means=means(~isnan(means))

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