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How to split an array of tot seconds in windows of 60 sec haveing also windows without values?

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francesca michelli
francesca michelli 2021-11-21
评论： dpb 2021-11-22
Hi,
I have an array of around 2000sec. I want to split it in windows of 60sec.
The problem is that i have windows without any values and i want to calculate the length of every segment. How can i do?
My code works but the problem is that i have some rows of my matrix (a and b) without values after the third row because there is nothing there so i get the error.
Here my code:
clc; clear all;
ampl = [0.200996832776533,0.108288299408268,0.0108131653866189,0.0148501982585796,0.0297382659490564,0.0205780518568360,0.0363249885477546,0.0199522268771810,0.0153020371754288,0.0107487246066077,0.0100465831465900,0.0115319065471520,0.0171852396573782,0.0171052921316926,0.0136866723178271,0.0405302764516071,0.0134629777880290,0.0441825338391930,0.0307994156746245,0.0129757976302988,0.0289983735876320,0.0107446774084927,0.0113938663682375,0.0779717262951948,0.0297679211454362,0.0104621364653687,0.0162760758676064,0.0172718901202518,0.0118598151578763,0.0204114935244239,0.0111905531897566,0.0243914430076990,0.0124411275457071,0.0224448043041579,0.0199145559228095,0.0257484947120200,0.0105671896452576,0.0158831603271501,0.0152644217085658,0.0108627619307609];
amp = round(ampl*100)/100
o = [0.250000000000000,2.50000000000000,7.50000000000000,18.5000000000000,22.5000000000000,34.2500000000000,70.5000000000000,72.2500000000000,78.5000000000000,150.250000000000,330.250000000000,336,336.500000000000,340.250000000000,341.500000000000,395.250000000000,1133.25000000000,1142.75000000000,1152.25000000000,1155.25000000000,1177,1179.75000000000,1191,1214,1215.75000000000,1217.25000000000,1271,1334.25000000000,1335,1336.75000000000,1337.75000000000,1391.25000000000,1429,1447.25000000000,1457.50000000000,1458.75000000000,1461.50000000000,1473.25000000000,1593.25000000000,1598.25000000000];
onset = round(o*100)/100
a = [];
b = [];
l = [];
m = [];
d = [];
M = [];
y=round(onset(length(onset))/60);
for i=1:y
for j=1:length(onset)
if onset(j)>=(i-1)*60+1 && onset(j)<=i*60
a(i,j)= onset(j);
b(i,j)= amp(j);
end
end
% l(i) = length(nonzeros(b(i,:))); ERROR!! Index in position 1 exceeds array bounds (must not exceed 3).

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回答（2 个）

dpb
dpb 2021-11-21
Use discretize. In paricular, look at the third input form where the bins, and input arrays are durations (iow, convert your time to a duration first).
Alternatively, if there's more than just one variable (or even if not), look at using timetable and retime instead.
NB: there's really no need for the rounding, but if do want to, also note the second optional argument to round()
>> ampl=round(ampl,2);
>> ampl(1:3)
ans =
0.20 0.11 0.01
>>
Star Strider
Star Strider 2021-11-21
I am not certain what the desired result is, however if I guess correctly the buffer function may be the solution.
.

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