Conditionally replace numerical Array with Strings

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Metin Akyol
Metin Akyol 2021-11-22
评论： Metin Akyol 2021-11-22
I have a simply array with 0s and 1s and I would like to replace each element conditionally with a string like so:
old_array = [0 1 0 0 1]
new_array = ["string0" "string1" "string0" "string0" "string1"]
I have tried this, but ended up with NaNs:
old_array(old_array>0)=string("string1")

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回答（1 个）

Dave B
Dave B 2021-11-22
Ran in:
This is happening because old_array is an array of doubles, you can't have a mix of strings and doubles in a regular (i.e. not cell) array.
You can convert an array to string and replace all of the values
old_array = [0 1 0 0 1];
old_array = "string" + string(old_array)
old_array = 1×5 string array
"string0" "string1" "string0" "string0" "string1"
Or convert the array to string and just replace some of the values (and still keep everything string):
old_array = [0 1 0 0 1];
ind = old_array>0;
old_array = string(old_array);
old_array(ind) = "string1"
old_array = 1×5 string array
"0" "string1" "0" "0" "string1"
Or you can use a cell array to mix and match types:
old_array = [0 1 0 0 1];
ind = old_array>0;
old_array = num2cell(old_array);
old_array(ind)={"string1"}
old_array = 1×5 cell array
{[0]} {["string1"]} {[0]} {[0]} {["string1"]}

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