What is this code is trying to do

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Nicle Davidson 2021-11-25

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https://ww2.mathworks.cn/matlabcentral/answers/1595589-what-is-this-code-is-trying-to-do

评论： Nicle Davidson 2021-11-25

Can you explain what this code is trying to do?

rot=[2,4,7,3,1,5,6,8]; disp(rot); for i=1:8 rot=mod(rot,8); rot=[rot(8)+1,rot(1:7)+1]; disp(rot); end

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Answer 1

Yusuf Suer Erdem 2021-11-25

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https://ww2.mathworks.cn/matlabcentral/answers/1595589-what-is-this-code-is-trying-to-do#answer_840074

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rot=[2,4,7,3,1,5,6,8]; 
disp(rot);                     %%% Display rot matrix
for i=1:8                      %%% this loop will turn 8 times
    rot=mod(rot,8);            %%% After this operation rot matrix will be---->[2,4,7,3,1,5,6,0]  because we are taking its mod according to 8 
                               %%% Each time rot matrix will be renewed (8 times)
    rot=[rot(8)+1,rot(1:7)+1]; %%% 'rot(8) + 1' means add rot matrix 8th member 1 (8 times)
                               %%% 'rot(1:7) + 1' means write rot matrix ' s members 1 to 7 and add 1 to each of them (8 times) 
    disp(rot);                 %%% display the final rot matrix (8 times)
end

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Rik 2021-11-25

在 MATLAB Online 中打开

I would also add that circshift would probably be more efficient, and since the number of shifts is equal to the number of elements, the shifts are only there for display purposes. Without the disp statements the loop would be equivalent to:

rot=mod(rot+8,8);

The +8 can even be removed, as x+8 mod 8 is equivalent to x mod 8.

Nicle Davidson 2021-11-25