If I'm understanding the problem correctly, you're trying to plot a series of histograms, where column 1 is merely ordinal information, and you want a histogram for each row.
% parameters
nbins = 20; % use however many bins you want
% test data
T = [1 0.3 0.2 0.3; 2 0.2 0.1 0.2 ; 3 0.7 0.9 0.7 ; 4 0.9 0.2 0.1];
% build histograms with fixed (common) binning
datarange = [min(T(:,2:end),[],'all') max(T(:,2:end),[],'all')];
edges = linspace(datarange(1),datarange(2),nbins+1);
numframes = size(T,1);
H = zeros(numframes,nbins);
for f = 1:numframes
H(f,:) = histcounts(T(f,2:end),edges);
end
% adjust bin labels to indicate bin center value
xticks = linspace(1,nbins,nbins);
hbw = 0.5*abs(diff(datarange))/(nbins+1);
xlabels = linspace(datarange(1)+hbw,datarange(2)-hbw,nbins);
% plot everything
h = bar3(H);
% color plots based on z instead of x
for k = 1:length(h)
h(k).CData = h(k).ZData;
h(k).FaceColor = 'interp';
h(k).EdgeAlpha = 0.5;
h(k).EdgeColor = [0 0 0];
end
set(gca,'xtick',xticks);
set(gca,'xticklabels',num2str(xlabels',3));
view(40,14)
xlabel('bin')
ylabel('frame')
colormap(jet)
This example uses a set of common, uniformly-distributed bins for all rows. If you want to let each row have its own bin locations, you can, but it'll pretty much make the xticks (bin location) unreadable since the bars won't align.
