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Carry prior cell forward until there is a new value

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IDN 2021-11-26

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评论： IDN 2021-11-27

I have a vector with possible 1,0,-1 as answers, each cell is the output of a statement/function. What I want is the following....If prior row is 0, then 1 can occur, and after 1 occurs i need it to continue populating rows below until statement outputs a -1 (also therefore -1 can only occur if prior row is 1).

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the cyclist 2021-11-26

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It would be very helpful to have a small, representative vector where you show us the input, and the desired output.

dpb 2021-11-26

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Concur w/ @the cyclist

If this is a static vector that contains the set of [1, 0, -1] that is one thing; if the function is supposed to be generating these as its results based on prior input, that's something else.

IDN 2021-11-27

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Thanks for looking into it, its something like this..

s = zeros(size(data_table));

s(var1>=2&var2<=10)=1;

s(var3>=20|var4>=46.53)=-1;

Output

dpb 2021-11-27

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OK, I think... :) Now to make it even easier for us, the input vector as either cut-n-paste text (its short). Use code format button and then we can just copy it -- or run in online.

IDN 2021-11-27

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Tables
A	B	C	D
12	11	6	1
3	5	18	30
4	6	17	20
1	8	5	8
12	15	25	9
1	2	5	9
11	12	19	25
12	15	16	20
9	15	5	8
1	2	8	2
1	1	15	40
8	9	19	45
15	16	17	45
7	9	5	10
0	8	16	18
4	5	19	33
1	0	15	50
0	15	19	48
1	1	16	20
1	20	18	40
s = zeros(size(A));
s(A>=2&B<=10)=1;
s(C>=20|D>=46.53)=-1;
Output
S
0
1
1
0
-1
0
0
0
0
0
0
1
0
1
0
1
-1
-1
0
0

DGM 2021-11-27

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Ran in:

Is there any issue just using a loop?

S = [0 1 1 0 0 -1 0 0 0 0 0 0 1 0 1 0 1 -1 -1 0]
S = 1×20
     0     1     1     0     0    -1     0     0     0     0     0     0     1     0     1     0     1    -1    -1     0
for k = 2:numel(S)
    m = [(S(k-1)==1) (S(k)~=-1)];
    if all(m)
        S(k) = 1;
    elseif all(~m)
        S(k) = 0;
    end
end
S
S = 1×20
     0     1     1     1     1    -1     0     0     0     0     0     0     1     1     1     1     1    -1     0     0