Creating a new array that contains number of overlap of non-zero values

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Aaron Devanathan
Aaron Devanathan 2021-11-28
评论： Image Analyst 2021-11-29
I have 4 equally sized arrays (under ARV.HEMEsubt_otsu), and the 'ARV' structure is attached with this question. I'm trying to create an array of equal size (105 x 107 double) that shows the total of the other arrays have non-zero values (i.e. 0, 1, 2, 3, or all 4). So for instance, at the row 75, column 57 cell location, only mz316 has a non-zero value so the new array would have a 1 in that cell in the new array.
I surmise a for loop that goes through the entire array and then assessing the others' cell values, but does anyone have any thoughts?
Happy to provide additional clarification as needed. Thanks!

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Image Analyst
Image Analyst 2021-11-28
编辑：Image Analyst 2021-11-28
Zeros add to zero, so why don't just add up those 4 arrays:
s=load('Arrays_11282021.mat')
s1 = s.ARV.HEMEsubt_otsu
m = s1.mz248 + ...
s1.mz288 + ...
s1.mz316 + ...
s1.mz445
imshow(m, [], 'InitialMagnification', 1600);
axis('on', 'image')
If you don't want the values themselves added, but just add 1 regardless ofthe value in there, just threshold at zero before adding:
s=load('Arrays_11282021.mat')
s1 = s.ARV.HEMEsubt_otsu
m = s1.mz248 > 0 + ...
s1.mz288 > 0 + ...
s1.mz316 > 0 + ...
s1.mz445 > 0
imshow(m, [], 'InitialMagnification', 1600);
axis('on', 'image')
  2 个评论
Aaron Devanathan
Aaron Devanathan 2021-11-29
Thanks @Image Analyst! I'll accept the answer. I'm curious: is there a way to display the image so that each number greater than 0 is its own color in the final array 'm'? Sorry if that's beyond the scope fo the question.
Image Analyst
Image Analyst 2021-11-29
Try this:
s = load('Arrays_11282021.mat')
s1 = s.ARV.HEMEsubt_otsu
m = uint8(s1.mz248 > 0) + ...
uint8(s1.mz288 > 0) + ...
uint8(s1.mz316 > 0) + ...
uint8(s1.mz445 > 0);
imshow(m, [], 'InitialMagnification', 1600);
axis('on', 'image')
impixelinfo; % Show (x,y) and value
colormap(lines(5))
colorbar

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