how to print randomly selected column?

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Haley Kelly 2021-12-10

评论： Image Analyst 2021-12-10

this is what i have, the data is 39,18

data = readtable('playlist.xlsx');

random_column = input('Would you like to print a random column? yes, no. ', 's');

if random_column == "yes"

x = randi(size(data,1));

column = data(:,x);

fprinf(column)

elseif random_column == "no"

fprintf('thats the end')

end

James Tursa 2021-12-10

编辑：James Tursa 2021-12-10

Shouldn't that be size(data,2)?

Also, generally you should be using string comparison functions for the tests, not the == operator. E.g.,

isequal(random_column,'yes')

strcmpi(random_column,'yes')

James Tursa 2021-12-10

编辑：James Tursa 2021-12-10

Because you have a typo. Should be fprintf, not fprinf

Also, fprintf( ) is typically used with a format string. To just print a variable you can use disp( ).

Image Analyst 2021-12-10

Or simply check if it starts with a y or Y

if startsWith(random_column, 'y', 'IgnoreCase', true)

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