creation of toeplitz matrix

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g
g 2021-12-15
评论： Star Strider 2021-12-15
Good morinig,
i have a cell matrix ( 6 x 1 ) where inside each cell i have a vector of two values. I would like to get a toeplitz matrix and I tried to use the command toeplitz(c,r) but I got the following error 'Inputs must be numeric'. In fact inside each cell I don't have a single value but a vector of two values.
What can i do? thanks

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回答（1 个）

Star Strider
Star Strider 2021-12-15
Ran in:
It would help to see the code, since I have no idea what ‘r’ is.
That aside, try something like this —
cell_matrix = {rand(1,2); rand(1,2); rand(1,2)}
cell_matrix = 3×1 cell array
{[0.8842 0.4232]} {[0.5807 0.8143]} {[0.9432 0.7645]}
r = rand(1,2)
r = 1×2
0.7594 0.9229
tm = toeplitz([cell_matrix{:}], r)
Warning: First element of input column does not match first element of input row.
Column wins diagonal conflict.
tm = 6×2
0.8842 0.9229 0.4232 0.8842 0.5807 0.4232 0.8143 0.5807 0.9432 0.8143 0.7645 0.9432
This indexing convention extracts the data in the comma-separated list of the cell array and concatenates it, creating a numeric vector. I have no idea if that numeric vector is the desired one. Another option is the cell2mat function.
See Access Data in Cell Array for more details.
.
  2 个评论
g
g 2021-12-15
编辑：g 2021-12-15
what I mean is that I have:
cell_matrix =
{[0.9503 0.5174]}
{[0.2850 0.6280]}
{[0.4221 0.3325]}
And from this array I want to get the toeplitz matrix:
toeplitz_matrix=
[0.9503 0.5174] [0 0 ][0 0 ]
[0.2850 0.6280] [0.9503 0.5174] [0 0 ]
[0.4221 0.3325][0.2850 0.6280] [0.9503 0.5174]
To do this I tried using
toeplitz(c,r)
where c corresponds to the first column and r to the first row. But I got the following error 'Inputs must be numeric'.
Star Strider
Star Strider 2021-12-15
Ran in:
It appears to be a ‘cell-of-cells’, so —
cell_matrix = { {[0.9503 0.5174]}
{[0.2850 0.6280]}
{[0.4221 0.3325]} }
cell_matrix = 3×1 cell array
{1×1 cell} {1×1 cell} {1×1 cell}
M = cellfun(@cell2mat, cell_matrix, 'Unif',0)
M = 3×1 cell array
{[0.9503 0.5174]} {[0.2850 0.6280]} {[0.4221 0.3325]}
M = cell2mat(M)
M = 3×2
0.9503 0.5174 0.2850 0.6280 0.4221 0.3325
c = M(:,1)
c = 3×1
0.9503 0.2850 0.4221
r = M(1,:)
r = 1×2
0.9503 0.5174
Tm = toeplitz(c, r)
Tm = 3×2
0.9503 0.5174 0.2850 0.9503 0.4221 0.2850
That would appear to be the desired result.
.

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