Splitting matrix into fixed rows and N columns

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daniele marchese
daniele marchese 2021-12-16
回答： daniele marchese 2021-12-16
Hello,
I have a matrix 3900x3. My goal is to rearrange it every 30x3 values in order to gain a resulting matrix of 30x130. I guess it is a simple task but I am pretty new into matlab codes and could not find any tips on the internet. Hope I clearly explained the problem
  2 个评论
Yazan
Yazan 2021-12-16
编辑：Yazan 2021-12-16
A 3900-by-3 matrix contains 11700 elements, but a 30-by-130 matrix has only 3900, so you can't just reshape the former to get to the latter. Explain better how to move from the first matrix to the second.
daniele marchese
daniele marchese 2021-12-16
I need to rearrange the 3900-by-3 [A B C] matrix concatenating it horizontally every 30-by-3 values.
So the resulting matrix will be 30-by [A B C A B C A B C ...] 390.

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采纳的回答

Torsten
Torsten 2021-12-16
编辑：Torsten 2021-12-16
M_new = M(1:30,:);
For i=2:130
M_new = horzcat(M_new, M(30*(i-1)+1:30*i,:)); % M is your original matrix (3900 x 3)
end

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daniele marchese
daniele marchese 2021-12-16
thank you a lot! it worked well.
much appreciated

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