Create a time vector from 01/01/1953 to 10/10/2010

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Derol sakpak 2021-12-17

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https://ww2.mathworks.cn/matlabcentral/answers/1613450-create-a-time-vector-from-01-01-1953-to-10-10-2010

评论： Eric Sofen 2022-4-12

Hello I am a beginner on matlab and I would like to create a time vector from 01/01/1953 to 10/10/2010. Then convert them to Julian day. Thank you

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Stephen23 2021-12-17

编辑：Stephen23 2021-12-18

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Here is a time vector that exactly fulfills your specification:

D = datetime([1953,2020],[1,10],[1,10])
D = 1×2 datetime array
   01-Jan-1953   10-Oct-2020

It is a vector going from 01/01/1953 to 10/10/2010. Because you did not specify the step size, it has a completely randomly selected step of 594096 hours, which just coincidentally happens to be the exact difference between those dates.

TIP: do NOT use outdated and deprecated DATENUM nor DATEVEC. Using robust DATETIME objects is much better:

dt = datetime(1953,1,1):calyears(10):datetime(2010,10,10)
dt = 1×6 datetime array
   01-Jan-1953   01-Jan-1963   01-Jan-1973   01-Jan-1983   01-Jan-1993   01-Jan-2003
jd = juliandate(dt)
jd = 1×6
	1.0e+00 *

                 2434378.5                 2438030.5                 2441683.5                 2445335.5                 2448988.5                 2452640.5

Eric Sofen 2022-4-12

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@Stephen, thanks for steering folks away from datenum and toward datetime.

You can also use the convertTo datetime function to get Julian dates, among other time conversions. The juliandate function lives in the Aerospace toolbox.

dt = datetime(1953,1,1):calyears(10):datetime(2010,10,10);
jd = convertTo(dt,"juliandate")
jd = 1×6
1.0e+06 *

    2.4344    2.4380    2.4417    2.4453    2.4490    2.4526