How to find index of first 3 maximum number in matrix
显示 更早的评论
I have the following function that n is the first 3 maximum value of matrix m:
m = [7;1;4;4;12;2;6;10;2];
temp = sort( m, 'descend' );
n = temp(1:3)
I need to know the index of matrix n, like:
p = [5;8;1]; % first max value in matrix m is 12 that it located in the fifth row
采纳的回答
use the second output argument of sort
m = [7;1;4;4;12;2;6;10;2];
[temp,originalpos] = sort( m, 'descend' );
n = temp(1:3)
p=originalpos(1:3)
1 个评论
Amit Kumar
2018-2-21
编辑：Amit Kumar
2018-2-21
Great.. I just want to add a comment that if you have NaN in your matrix replace beforehand as m(isnan(m))=0 and then use, as:
m = [7;1;4;4;NaN;2;6;10;2];
m(isnan(m))=0
[temp,originalpos] = sort( m, 'descend' );
n = temp(1:3)
p=originalpos(1:3)
更多回答（2 个）
m = [7;1;4;4;12;2;6;10;2];
temp = sort( m, 'descend' );
n = temp(1:3);
for i=1:9
if n(1)==m(i)
p1=i;
elseif n(2)==m(i)
p2=i;
elseif n(3)==m(i)
p3=i;
end
end
p=[p1 p2 p3]
类别
在 帮助中心 和 File Exchange 中查找有关 Matrices and Arrays 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
