parfor loop and decimal step increments in variable

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IDN
IDN 2021-12-30
评论： IDN 2021-12-30
Hello, What is the best way to be able to use a "parfor" loop when you have a variable that uses a decimal step as below...
yHH = 1:0.1:3;
parfor yA = 3:6
for yC = 10:20
for yHper = 2:5
for yH = 1:length(yHH)
for yV = 50:60
Function(yA,yC,yHper,yH,yV);
end
end
end
end
end
Thanks!

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采纳的回答

Walter Roberson
Walter Roberson 2021-12-30
yH_vals = 1:0.1:3; n_yH = length(yH_vals);
yA_vals = 3:6; n_yA = length(yA_vals);
yC_vals = 10:20; n_yC = length(yC_vals);
yHper_vals = 2:5; n_yHper = length(yHper_vals);
yV_vals = 50:60; n_yV = length(yV_vals);
parfor yAidx = 1:n_yA
yA = yA_vals(yAidx);
for yCidx = 1:n_yC
yC = yC_vals(yCidx);
for yHperidx = 1:n_yHper
yHper = yHper_vals(yHperidx);
for yHidx = 1:n_yH
yH = yH_vals(yHidx);
for yVidx = 1 : n_yV
yV = yV_vals(yVidx);
YourOutput(yVidx, yHidx, yHperidx, yCidx, yAidx) = YourFunction(yA, yC, yHper, yH, yV);
end
end
end
end
end
And if you really want, then afterwards,
YourOutput = permute(YourOutput, [6 5 4 3 2 1]);
Using the inner loop variable as the first index is most efficient for memory access; especially with multidimensional arrays, the difference can be quite notable.

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