How can I make randi() in a loop not choose the same number

2 次查看（过去 30 天）
Tariq Hammoudeh
Tariq Hammoudeh 2022-1-8
回答： Walter Roberson 2022-1-8
I have an array
x=zeros(1,36)
then i have inside a while loop:
while ....
y=randi(length(x));
z=randi(length(x));
How can i make it so that this doesnt choose the same number at all,
Note: the loop will end before it gets to 36 choices, so its not that it doesnt have a choice but to go over the same numbers again

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2022-1-8
That would be a bit difficult. You would have to find a random number seed that you could set such that randi(36) happens to produce a permutation of the numbers 1 : 36. It could take a fair bit of work to find such a seed.
I would suggest that you take a completely different approach:
rand_y = randperm(length(x));
rand_z = randperm(length(x));
for K = 1 : length(x)
y = rand_y(K);
z = rand_z(K);
stuff
if some conditon;
break;
end
end

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

产品


版本

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by