substituting value in matrix does not work for some reason

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Bogdan
Bogdan 2014-11-18
编辑： Kelly Kearney 2014-11-18
A = [6 9 NaN NaN 8 NaN]; B = [2 5 342 232 1 116];
sizeA = size(A);
for m = [1:1:size(2)];
if A(1,m) == NaN;
B(1,m) = NaN;
end;
end;
I was hoping B would become [2 5 NaN NaN 8 NaN], but it did not change. I would appreciate any help

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采纳的回答

Kelly Kearney
Kelly Kearney 2014-11-18
编辑：Kelly Kearney 2014-11-18
You can't use == with NaNs:
>> NaN == NaN
ans =
0
Use isnan instead:
B(isnan(A)) = NaN;

更多回答（1 个）

Kevin Claytor
Kevin Claytor 2014-11-18
Logical indexing makes this much easier;
B(A==NaN) = NaN;

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