Is it possible to reconstruct an image from the number of pixel counts and bins information?

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Gobert
Gobert 2022-1-20
评论： Gobert 2022-1-21
Happy New Year and I need your help!
I have the following imhist function that yields the number of pixel counts and bin locations.
[counts,binLocations] = imhist(I)
Is it possible to reconstruct a "new" image using the number of "new pixel" counts and "same" bins information? If yes - can you please suggest how?

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采纳的回答

Walter Roberson
Walter Roberson 2022-1-20
Ran in:
I = imread('pout.tif');
imshow(I)
I1 = reshape(sort(I), size(I));
imshow(I1)
[c,b] = imhist(I);
[c1,b1] = imhist(I1);
all(c == c1)
ans = logical
1
all(b == b1)
ans = logical
1
Two different images, exactly the same counts and bin values.
It follows that knowing the counts and bin locations is not enough to recreate the image.

更多回答（1 个）

Matt J
Matt J 2022-1-20
编辑：Matt J 2022-1-20
Ran in:
As Walter has shown, it is not an invertible mapping, however, if you use histcounts() instead, there is enough information for a coarse inversion:
I = double(imread('pout.tif'));
[counts,binLocations,label]=histcounts(I(:),4);
vals=movmean(binLocations,2);
Irecon=reshape(vals(label), size(I)); %reconstructed
montage({I/255,Irecon/255})

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