How do I convert tall array duration time vector to HH:mm:ss for merging with tall array datetime vector ?

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Need some help with this. I have a tall array date vector 'yyyy-MM-dd' of datetime format, and a tall array time vector 'HH:mm:ss.SSS' of duration format. How do I convert the duration vector to only HH:mm:ss (omitting the decimals) and then combine that with the date vector to get: 'yyyy-MM-dd HH:mm:ss' ?

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Chris
Chris 2022-1-21
dates = tall(repmat(datetime(date),3,1))
dates = 3×1 tall datetime array 21-Jan-2022 21-Jan-2022 21-Jan-2022
times = tall(repmat(duration(15,12,1,345,'Format','hh:mm:ss.SSS'),3,1))
times = 3×1 tall duration array 15:12:01.345 15:12:01.345 15:12:01.345
times.Format = 'hh:mm:ss';
datetime([string(dates) + " " + string(times)])
ans = 3×1 tall datetime array 21-Jan-2022 15:12:01 21-Jan-2022 15:12:01 21-Jan-2022 15:12:01
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Chris
Chris 2022-4-19
编辑:Chris 2022-4-19
Hello again, Douglas.
How about the following?
dates = datestr(theTable{:,1},'dd-mmm-yyyy');
durs = datestr(theTable{:,2},'HH:MM:SS');
merged = datetime(dates + " " + durs);
You could also shift the table around:
theTable.Var1 = merged;
theTable.Var2 = [];

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更多回答(1 个)

Walter Roberson
Walter Roberson 2022-1-21
perhaps
[h,m,s] = hms(DURATION_COLUMN);
DATETIME_COLUMN = TIME_COLUMN + duration(h,m,floor(s))
or perhaps
DATETIME_COLUMN = dateshift(TIME_COLUMN + DURATION_COLUMN, 'start', 'second')
if you do not have negative durations or negative datetimes, then adding first and then getting rid of the fractions of a second should give the same result.

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