Iterate through matrix until no more possible calculations.

1 次查看（过去 30 天）
DuckDuck
DuckDuck 2014-11-19
回答： Thorsten 2014-11-19
I have an array that shortens up every time i do an iteration. But how do i know when there are no more possible calculations to be done and the size of the array cannot be shortened up any more. i'm thinking using while loop but don't know how to check it. Any help please.
Suppose i have a matrix
a=[1,2;
1,3;
1,4;
2,12;
2,15;
5,7;
5,8;
6,98;
6,99;
7,8;
7,9;
7,11;
9,14;
9,16;
12,18;
14,20;
20,35;
98,102;
99,204;
204,300;
301,305;
308,400];
every time i do an iteration i remove the elements of one of the arrays below. first
b=[1,2,3,4,12,15,18],
then
c=[5,7,8,9,14,16,20,35],
then
d=[6,98,99,102,204,300] and i'm left with
a=[301,305;308,400].
So how do i know there are no more iterations to go?

请先登录，再回答此问题。

采纳的回答

Thorsten
Thorsten 2014-11-19
Store the b, c, d arrays as cell elements in cell b. Then insert the i'th row of a into anew if its not element of any list in b.
anew = [];
for i = 2:size(a, 1)
bi = 1;
while bi <= numel(b) && isempty(intersect(a(i,:), b{bi}))
bi = bi + 1;
end
if bi > numel(b) % a(i,:) not member of any b{bi}
anew(end+1,:) = a(i,:);
end
end
disp('anew')
disp(anew)

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by