Time series syntax question

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Stefan 2014-11-26

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回答： Image Analyst 2014-11-26

Hi everyone, I'm using a template for a homework assignment in MATLAB. I'm having trouble with a section that seems to require time series, but I can't find any info on this particular type. The code is: ts(i,1) =%fill in here . I've never seen the ts(i,1) syntax before, and can't find any info on it anywhere. Can anyone explain to me what this means?

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per isakson 2014-11-26

Did you read this? Looks like a starting point to me.

Time Series Basics

Stefan 2014-11-26

I read these, but none of them go over this syntax, unless I just don't recognize it, which is also very likely.

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Answer 1

Image Analyst 2014-11-26

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ts(i, 1) refers to the element of the ts array in the i'th row and the first column. Assuming i is a single number , like 5 or whatever, then ts(i,1) would be assigned a single number, like 73 or whatever.

ts(i, 1) = 73;

If i = 5, this would assign ts(5,1) a value of 73.

If i is an array of numbers or array of logicals then ts(i,1) would assign a bunch of rows in the first column. Like if i were [2,4,8], ts(i,1) would need to take 3 numbers, like

ts(i, 1) = [22,34,88];

This would assign element ts(2,1) to 22, element ts(4,1) to 34, and assign element ts(8,1) to 88. I hope that explains it better.

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Answer 2

Youssef Khmou 2014-11-26

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ts(i,1) means performing calculation of the elements of first column of matrix ts, ts(i,2) means the ith element on the second column, ( use other variable instead of i, i is the imaginary number )

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Stefan 2014-11-26

编辑：per isakson 2014-11-26

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So what would I even put after the equals sign? I'm still confused. This is the rest of the code leading up to that point, if this helps any:

    function out = main()
    close all;
    pars=[4 10 1 20 1 20];
    k1=pars(1);
    k2=pars(2);
    k3=pars(3);
    k4=pars(4);
    k5=pars(5);
    k6=pars(6);
    init=[10 10 10];
    steps = 500000;
    ts= zeros(steps+1,4);
    ts(1,2:4) = init;
    a=ts(1,2);
    b=ts(1,3);
    c=ts(1,4);
    for i = 2:(steps+1)
        lmd1 = k1*a*b;
        lmd2 = c*k2;
        lmd3 = a*k3;
        lmd4 = k4;
        lmd5 = b*k5;
        lmd6 = k6;
        rate = [lmd1 lmd2 lmd3 lmd4 lmd5 lmd6];
        lmd = sum(rate);
        p= cumsum(rate)/lmd;
        U = rand(1,2);