Time series syntax question

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Stefan
Stefan 2014-11-26
回答： Image Analyst 2014-11-26
Hi everyone, I'm using a template for a homework assignment in MATLAB. I'm having trouble with a section that seems to require time series, but I can't find any info on this particular type. The code is: ts(i,1) =%fill in here . I've never seen the ts(i,1) syntax before, and can't find any info on it anywhere. Can anyone explain to me what this means?
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per isakson
per isakson 2014-11-26
Did you read this? Looks like a starting point to me.
Stefan
Stefan 2014-11-26
I read these, but none of them go over this syntax, unless I just don't recognize it, which is also very likely.

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采纳的回答

Image Analyst
Image Analyst 2014-11-26
ts(i, 1) refers to the element of the ts array in the i'th row and the first column. Assuming i is a single number , like 5 or whatever, then ts(i,1) would be assigned a single number, like 73 or whatever.
ts(i, 1) = 73;
If i = 5, this would assign ts(5,1) a value of 73.
If i is an array of numbers or array of logicals then ts(i,1) would assign a bunch of rows in the first column. Like if i were [2,4,8], ts(i,1) would need to take 3 numbers, like
ts(i, 1) = [22,34,88];
This would assign element ts(2,1) to 22, element ts(4,1) to 34, and assign element ts(8,1) to 88. I hope that explains it better.

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Youssef Khmou
Youssef Khmou 2014-11-26
ts(i,1) means performing calculation of the elements of first column of matrix ts, ts(i,2) means the ith element on the second column, ( use other variable instead of i, i is the imaginary number )
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Stefan
Stefan 2014-11-26
编辑：per isakson 2014-11-26
So what would I even put after the equals sign? I'm still confused. This is the rest of the code leading up to that point, if this helps any:
function out = main()
close all;
pars=[4 10 1 20 1 20];
k1=pars(1);
k2=pars(2);
k3=pars(3);
k4=pars(4);
k5=pars(5);
k6=pars(6);
init=[10 10 10];
steps = 500000;
ts= zeros(steps+1,4);
ts(1,2:4) = init;
a=ts(1,2);
b=ts(1,3);
c=ts(1,4);
for i = 2:(steps+1)
lmd1 = k1*a*b;
lmd2 = c*k2;
lmd3 = a*k3;
lmd4 = k4;
lmd5 = b*k5;
lmd6 = k6;
rate = [lmd1 lmd2 lmd3 lmd4 lmd5 lmd6];
lmd = sum(rate);
p= cumsum(rate)/lmd;
U = rand(1,2);
per isakson
per isakson 2014-11-26
Here you assign an array of double to a variable named, ts. Confusing!

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