ismember for string matrix

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Sam
Sam 2014-11-26
评论： Sean de Wolski 2014-11-26
I have two string matrices;
A=['c1' 'c ' 'b ' 'd9']'; %UNIQUELIST
B=['d9' 'c1']'; %ORIGINALLIST
I would like do find member of B in A, using:
[LIA,LOCB]=ismember(A,B);
and it returns
LOCB =
3
4
3
0
0
0
1
2
But I actually would like it to return matching row index like this:
LOCB =
2
0
0
1
Thanks for your help
Sam

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回答（2 个）

Sean de Wolski
Sean de Wolski 2014-11-26
You need to make A and B cell arrays so that each string piece is a separate element (rather than a 1xn string. The fix is simple use {} instead of []
A={'c1' 'c ' 'b ' 'd9'}';
B={'d9' 'c1'}'
[LIA,LOCB]=ismember(A,B)
dpb
dpb 2014-11-26
You've got string arrays here; use the 'rows' optional argument to treat them as such instead of as individual characters...
>> [~,loc]=ismember(A,B,'rows')
loc =
2
0
0
1
>>
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dpb
dpb 2014-11-26
Did you try it and see???
Sean de Wolski
Sean de Wolski 2014-11-26
Probably, but converting to cells is heavier weight if you don't need them for other things.

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