parfor. Error: The variable eavg in a parfor cannot be classified.

1 次查看（过去 30 天）
Marco Castelli
Marco Castelli 2014-12-2
评论： Mohammad Abouali 2014-12-3
I have already read other topic on Errors and parfor but i don't find the answer to my problem.
My code give me an Error: "Error: The variable eavg in a parfor cannot be classified."
The pice of code with parfor is:
eavg = zeros(size(coeff_d,2),size(coeff_c,2),size(f,1));
parfor i0 = 1:size(vett,2)
i1 = vett(1,i0);
i2 = vett(2,i0);
i3 = vett(3,i0);
if curva~=2
if curva==4
z_rel = (i3-1)/(size(y,1)-1);
newcoeff = (-1.817*(z_rel)^2+2.776*z_rel)*0.7;
else
newcoeff = coeff_c(i2);
end
suptemp = EsponenzialeSingola(y(i3,:), f(i3,:),...
coeff_d(i1), newcoeff, plottacurve);
else
eavg(i1,i2,i3) = EsponenzialeDoppia(y(i3,:), f(i3,:),...
coeff_d(i1), coeff_c(i2), plottacurve);
end
end
the variables coeff_c, coeff_d, f, coeff_c, vett, curva, y and plottacurva are declared befor parfor-loop.
Can you help e to fix the Error?

请先登录，再回答此问题。

采纳的回答

Mohammad Abouali
Mohammad Abouali 2014-12-2
your parfor is based on i0 eavg is not being sliced by that.
So it doesn't know how to slice eavg and then once it comes out of parfor it doesn't know how to combins it.

更多回答（1 个）

Marco Castelli
Marco Castelli 2014-12-3
编辑：Marco Castelli 2014-12-3
@Mohammad Abouali : Thanks to you help I solve the problem in this way:
parfor i0 = 1:size(vett,2)
if curva~=2
if curva==4
z_rel = (vett(3,i0)-1)/(size(y,1)-1);
newcoeff = (-1.817*(z_rel)^2+2.776*z_rel)*0.7;
else
newcoeff = coeff_c(vett(2,i0));
end
eavg(i0) = EsponenzialeSingola(y(vett(3,i0),:), f(vett(3,i0),:),...
coeff_d(vett(1,i0)), newcoeff, plottacurve);
else
eavg(i0) = EsponenzialeDoppia(y(vett(3,i0),:), f(vett(3,i0),:),...
coeff_d(vett(1,i0)), coeff_c(vett(2,i0)), plottacurve);
end
end

类别

在 Help Center 和 File Exchange 中查找有关 Parallel for-Loops (parfor) 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by