How to create matrix array using while loop and time increment?

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I have a problem where i want to solve a problem where an apple falls from a tree from 3m before hitting the ground. Assuming there is no air resistance, how long will it take to hit the ground? I have to create an array with time increments until the distance becomes 0 at the final time. So first column should show my time and second column will show the distance going down at every increment.
y0=2;
g=-9.81;
t = 0;
i=0;
y1=y0;
a = zeros([],2);
while y1>=0
i=i+1;
t=t+0.10;
y1=y0-0.5*g*t.^2;
a(i,:) = [t,y1]
end
disp(a)
0.0065 2.0726 %sample results
0.0065 2.0789
0.0065 2.0853
0.0065 2.0917
0.0065 2.0981
0.0066 2.1046
0.0066 2.1110
0.0066 2.1174
But when I run my code, it won't stop running and instead of 0.10 increments, the time looks off. How do I use the while loop (must use) to find the time it takes for the final y value to be 0.

采纳的回答

DGM
DGM 2022-2-16
编辑:DGM 2022-2-16
Well, that's what happens when you drop an anti-gravity apple.
y0 = 2;
g = -9.81;
tstep = 0.01;
t = 0;
i = 0;
y1 = y0;
a = zeros([],2);
while y1 >= 0
i = i + 1;
t = t + tstep;
y1 = y0 + 0.5*g*t.^2;
a(i,:) = [t,y1];
end
plot(a(:,1),a(:,2))
  1 个评论
Kenny Gee
Kenny Gee 2022-2-16
okay, i see where i made my mistake. sorry about the actual equation. I wanted to learn to do while loop. Thank you :)

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更多回答(1 个)

David Hill
David Hill 2022-2-16
y1=y0+0.5*g*t.^2;%needs to be + (gravity is negative)

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